-- clear data
delete from blocks; delete from transactions; delete from transaction_inputs; delete from transaction_outputs; delete from balances;

-- avg time to get a new block
SELECT AVG(b.time - a.time) AS new_block_avg_time
FROM (SELECT height, time FROM blocks) a JOIN
     (SELECT height, time FROM blocks) b ON (a.height + 1 = b.height);

-- print the number of transactions per block and count how many blocks have that number
SELECT txcount, COUNT(*) AS times
FROM (
  SELECT COUNT(txid) AS txcount, height
  FROM blocks LEFT JOIN transactions USING (blockhash)
  GROUP BY height) tmp
GROUP BY txcount
ORDER BY txcount;

-- find corrupted balances
SELECT address, one.available AS one, (two.received - two.spent) AS two
FROM (
    SELECT address, received - spent AS available
    FROM (
        SELECT address, SUM(value) AS spent
        FROM transaction_inputs
        GROUP BY address
      ) s JOIN
      (
        SELECT address, SUM(value) AS received
        FROM transaction_outputs
        GROUP BY address
      ) r USING (address)
  ) one JOIN balances two USING (address)
WHERE one.available <> (two.received - two.spent);
--

-- rebuild balances table
-- 1. count number of balances
SELECT COUNT(*)
FROM balances;

-- 2. verify you would write the same amount
SELECT COUNT(*)
FROM
  (
    SELECT address, SUM(value) AS received
    FROM transaction_outputs
    GROUP BY address
  ) r LEFT JOIN (
      SELECT address, SUM(value) AS spent
      FROM transaction_inputs
      GROUP BY address
  ) s USING (address);

-- 3. delete balances, be sure that the explorer is turned off
DELETE FROM balances;

-- 4. insert the balances
INSERT INTO balances
  (
    SELECT address, received, COALESCE(spent, 0) AS spent
    FROM
      (
        SELECT address, SUM(value) AS received
        FROM transaction_outputs
        GROUP BY address
      ) r LEFT JOIN (
          SELECT address, SUM(value) AS spent
          FROM transaction_inputs
          GROUP BY address
      ) s USING (address)
  );

-- 5. verify you have the same amount
SELECT COUNT(*) FROM balances;

-- 6. start explorer