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use base43 in order to send transactions by QR code

283
ThomasV 10 years ago
parent
commit
46c290e30d
  1. 4
      gui/qt/main_window.py
  2. 4
      gui/qt/transaction_dialog.py
  3. 47
      lib/bitcoin.py

4
gui/qt/main_window.py

@ -2240,8 +2240,8 @@ class ElectrumWindow(QMainWindow):
return
# else if the user scanned an offline signed tx
# transactions are binary, but qrcode seems to return utf8...
import base64
z = base64.b64decode(data.decode('utf8'))
data = data.decode('utf8')
z = bitcoin.base_decode(data, length=None, base=43)
data = ''.join(chr(ord(b)) for b in z).encode('hex')
tx = self.tx_from_text(data)
if not tx:

4
gui/qt/transaction_dialog.py

@ -34,6 +34,7 @@ from PyQt4.QtCore import *
import PyQt4.QtCore as QtCore
from electrum import transaction
from electrum.bitcoin import base_encode
from electrum.plugins import run_hook
from util import MyTreeWidget
@ -108,9 +109,8 @@ class TxDialog(QDialog):
def show_qr(self):
import base64
text = self.tx.raw.decode('hex')
text = base64.b64encode(text)
text = base_encode(text, base=43)
try:
self.parent.show_qrcode(text, 'Transaction')
except Exception as e:

47
lib/bitcoin.py

@ -239,73 +239,76 @@ def hash_160_to_bc_address(h160, addrtype = 0):
vh160 = chr(addrtype) + h160
h = Hash(vh160)
addr = vh160 + h[0:4]
return b58encode(addr)
return base_encode(addr, base=58)
def bc_address_to_hash_160(addr):
bytes = b58decode(addr, 25)
bytes = base_decode(addr, 25, base=58)
return ord(bytes[0]), bytes[1:21]
__b58chars = '123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz'
__b58base = len(__b58chars)
assert len(__b58chars) == 58
__b43chars = '0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ$*+-./:'
assert len(__b43chars) == 43
def b58encode(v):
""" encode v, which is a string of bytes, to base58."""
def base_encode(v, base):
""" encode v, which is a string of bytes, to base58."""
if base == 58:
chars = __b58chars
elif base == 43:
chars = __b43chars
long_value = 0L
for (i, c) in enumerate(v[::-1]):
long_value += (256**i) * ord(c)
result = ''
while long_value >= __b58base:
div, mod = divmod(long_value, __b58base)
result = __b58chars[mod] + result
while long_value >= base:
div, mod = divmod(long_value, base)
result = chars[mod] + result
long_value = div
result = __b58chars[long_value] + result
result = chars[long_value] + result
# Bitcoin does a little leading-zero-compression:
# leading 0-bytes in the input become leading-1s
nPad = 0
for c in v:
if c == '\0': nPad += 1
else: break
return (__b58chars[0]*nPad) + result
return (chars[0]*nPad) + result
def b58decode(v, length):
def base_decode(v, length, base):
""" decode v into a string of len bytes."""
if base == 58:
chars = __b58chars
elif base == 43:
chars = __b43chars
long_value = 0L
for (i, c) in enumerate(v[::-1]):
long_value += __b58chars.find(c) * (__b58base**i)
long_value += chars.find(c) * (base**i)
result = ''
while long_value >= 256:
div, mod = divmod(long_value, 256)
result = chr(mod) + result
long_value = div
result = chr(long_value) + result
nPad = 0
for c in v:
if c == __b58chars[0]: nPad += 1
if c == chars[0]: nPad += 1
else: break
result = chr(0)*nPad + result
if length is not None and len(result) != length:
return None
return result
def EncodeBase58Check(vchIn):
hash = Hash(vchIn)
return b58encode(vchIn + hash[0:4])
return base_encode(vchIn + hash[0:4], base=58)
def DecodeBase58Check(psz):
vchRet = b58decode(psz, None)
vchRet = base_decode(psz, None, base=58)
key = vchRet[0:-4]
csum = vchRet[-4:]
hash = Hash(key)

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