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pytest: Add local_add tests to test_gossip_persistence and cleanup

Mixing the test into the existing test allows us to reduce the execution, but
adds a bit of complexity, so I added two small helpers.

Signed-off-by: Christian Decker <decker.christian@gmail.com>
ppa-0.6.1
Christian Decker 7 years ago
parent
commit
140123b4c8
  1. 48
      tests/test_lightningd.py

48
tests/test_lightningd.py

@ -2278,23 +2278,34 @@ class LightningDTests(BaseLightningDTests):
l1 = self.node_factory.get_node(options=opts)
l2 = self.node_factory.get_node(options=opts)
l3 = self.node_factory.get_node(options=opts)
l4 = self.node_factory.get_node(options=opts)
l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port'])
l2.rpc.connect(l3.info['id'], 'localhost', l3.info['port'])
l3.rpc.connect(l4.info['id'], 'localhost', l4.info['port'])
self.fund_channel(l1, l2, 10**6)
self.fund_channel(l2, l3, 10**6)
l1.bitcoin.rpc.generate(6)
# Make channels public, except for l3 -> l4, which is kept local-only for now
l1.bitcoin.rpc.generate(5)
self.fund_channel(l3, l4, 10**6)
l1.bitcoin.rpc.generate(1)
def count_active(node):
chans = node.rpc.listchannels()['channels']
active = [c for c in chans if c['active']]
print(len(active), active)
return len(active)
# Channels should be activated
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True] * 4)
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels()['channels']] == [True] * 4)
wait_for(lambda: [c['active'] for c in l3.rpc.listchannels()['channels']] == [True] * 4)
wait_for(lambda: count_active(l1) == 4)
wait_for(lambda: count_active(l2) == 4)
wait_for(lambda: count_active(l3) == 5) # 4 public + 1 local
# l1 restarts and doesn't connect, but loads from persisted store
l1.restart()
assert [c['active'] for c in l1.rpc.listchannels()['channels']] == [True] * 4
wait_for(lambda: count_active(l1) == 4)
# Now spend the funding tx, generate a block and see others deleting the
# channel from their network view
@ -2302,13 +2313,32 @@ class LightningDTests(BaseLightningDTests):
time.sleep(1)
l1.bitcoin.rpc.generate(1)
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True] * 2)
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels()['channels']] == [True] * 2)
wait_for(lambda: [c['active'] for c in l3.rpc.listchannels()['channels']] == [True] * 2)
sync_blockheight([l1, l2, l3, l4])
wait_for(lambda: count_active(l1) == 2)
wait_for(lambda: count_active(l2) == 2)
wait_for(lambda: count_active(l3) == 3) # 2 public + 1 local
# We should have one local-only channel
def count_non_public(node):
chans = node.rpc.listchannels()['channels']
nonpublic = [c for c in chans if not c['public']]
return len(nonpublic)
# The channel l3 -> l4 should be known only to them
assert count_non_public(l1) == 0
assert count_non_public(l2) == 0
wait_for(lambda: count_non_public(l3) == 1)
wait_for(lambda: count_non_public(l4) == 1)
# Finally, it should also remember the deletion after a restart
l3.restart()
assert [c['active'] for c in l3.rpc.listchannels()['channels']] == [True] * 2
l4.restart()
wait_for(lambda: count_active(l3) == 3) # 2 public + 1 local
# Both l3 and l4 should remember their local-only channel
wait_for(lambda: count_non_public(l3) == 1)
wait_for(lambda: count_non_public(l4) == 1)
def ping_tests(self, l1, l2):
# 0-byte pong gives just type + length field.

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