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pytest: more thorough tests for HTLC confusion. 

We set up HTLCs with the same preimage and both different and same
CLTVs in both directions, then make sure that onchaind is OK and that
the HTLCs are failed without causing downstream failure.

We do this for both our-unilateral and their-unilateral cases.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
ppa-0.6.2rc1
Rusty Russell 6 years ago
committed by Christian Decker
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a4dbd6e0f0
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1 changed files with 253 additions and 0 deletions
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  1. 253
      tests/test_closing.py

253
tests/test_closing.py
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@ -1025,6 +1025,259 @@ def test_permfail_new_commit(node_factory, bitcoind, executor):
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
def setup_multihtlc_test(node_factory, bitcoind):
# l1 -> l2 -> l3 -> l4 -> l5 -> l6 -> l7
# l1 and l7 ignore and HTLCs they're sent.
# For each direction, we create these HTLCs with same payment_hash:
# 1 failed (CLTV1)
# 1 failed (CLTV2)
# 2 live (CLTV2)
# 1 live (CLTV3)
nodes = node_factory.line_graph(7, announce=True,
opts={'dev-no-reconnect': None,
'may_reconnect': True})
# Balance by pushing half the funds.
b11 = nodes[-1].rpc.invoice(10**9 // 2, '1', 'balancer')['bolt11']
nodes[0].rpc.pay(b11)
nodes[0].rpc.dev_ignore_htlcs(id=nodes[1].info['id'], ignore=True)
nodes[-1].rpc.dev_ignore_htlcs(id=nodes[-2].info['id'], ignore=True)
preimage = "0" * 64
h = nodes[0].rpc.invoice(msatoshi=10**8, label='x', description='desc',
preimage=preimage)['payment_hash']
nodes[-1].rpc.invoice(msatoshi=10**8, label='x', description='desc',
preimage=preimage)['payment_hash']
# First, the failed attempts (paying wrong node). CLTV1
r = nodes[0].rpc.getroute(nodes[-2].info['id'], 10**8, 1)["route"]
nodes[0].rpc.sendpay(r, h)
with pytest.raises(RpcError, match=r'UNKNOWN_PAYMENT_HASH'):
nodes[0].rpc.waitsendpay(h)
r = nodes[-1].rpc.getroute(nodes[1].info['id'], 10**8, 1)["route"]
nodes[-1].rpc.sendpay(r, h)
with pytest.raises(RpcError, match=r'UNKNOWN_PAYMENT_HASH'):
nodes[-1].rpc.waitsendpay(h)
# Now increment CLTV -> CLTV2
bitcoind.generate_block(1)
sync_blockheight(bitcoind, nodes)
# Now, the live attempts with CLTV2 (blackholed by end nodes)
r = nodes[0].rpc.getroute(nodes[-1].info['id'], 10**8, 1)["route"]
nodes[0].rpc.sendpay(r, h)
r = nodes[-1].rpc.getroute(nodes[0].info['id'], 10**8, 1)["route"]
nodes[-1].rpc.sendpay(r, h)
# We send second HTLC from different node, since they refuse to send
# multiple with same hash.
r = nodes[1].rpc.getroute(nodes[-1].info['id'], 10**8, 1)["route"]
nodes[1].rpc.sendpay(r, h)
r = nodes[-2].rpc.getroute(nodes[0].info['id'], 10**8, 1)["route"]
nodes[-2].rpc.sendpay(r, h)
# Now increment CLTV -> CLTV3.
bitcoind.generate_block(1)
sync_blockheight(bitcoind, nodes)
r = nodes[2].rpc.getroute(nodes[-1].info['id'], 10**8, 1)["route"]
nodes[2].rpc.sendpay(r, h)
r = nodes[-3].rpc.getroute(nodes[0].info['id'], 10**8, 1)["route"]
nodes[-3].rpc.sendpay(r, h)
# Make sure HTLCs have reached the end.
nodes[0].daemon.wait_for_logs(['peer_in WIRE_UPDATE_ADD_HTLC'] * 3)
nodes[-1].daemon.wait_for_logs(['peer_in WIRE_UPDATE_ADD_HTLC'] * 3)
return h, nodes
@pytest.mark.xfail(strict=True)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for dev_ignore_htlcs")
def test_onchain_multihtlc_our_unilateral(node_factory, bitcoind):
"""Node pushes a channel onchain with multiple HTLCs with same payment_hash """
h, nodes = setup_multihtlc_test(node_factory, bitcoind)
mid = len(nodes) // 2
for i in range(len(nodes) - 1):
assert only_one(nodes[i].rpc.listpeers(nodes[i + 1].info['id'])['peers'])['connected']
# Now midnode goes onchain with n+1 channel.
nodes[mid].rpc.dev_fail(nodes[mid + 1].info['id'])
nodes[mid].wait_for_channel_onchain(nodes[mid + 1].info['id'])
bitcoind.generate_block(1)
nodes[mid].daemon.wait_for_log(' to ONCHAIN')
nodes[mid + 1].daemon.wait_for_log(' to ONCHAIN')
# Now, restart and manually reconnect end nodes (so they don't ignore HTLCs)
# In fact, they'll fail them with WIRE_TEMPORARY_NODE_FAILURE.
nodes[0].restart()
nodes[-1].restart()
# We disabled auto-reconnect so we'd detect breakage, so manually reconnect.
nodes[0].rpc.connect(nodes[1].info['id'], 'localhost', nodes[1].port)
nodes[-1].rpc.connect(nodes[-2].info['id'], 'localhost', nodes[-2].port)
# Wait for HTLCs to stabilize.
nodes[0].daemon.wait_for_logs(['peer_out WIRE_UPDATE_FAIL_HTLC'] * 3)
nodes[0].daemon.wait_for_log('peer_out WIRE_COMMITMENT_SIGNED')
nodes[0].daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
nodes[-1].daemon.wait_for_logs(['peer_out WIRE_UPDATE_FAIL_HTLC'] * 3)
nodes[-1].daemon.wait_for_log('peer_out WIRE_COMMITMENT_SIGNED')
nodes[-1].daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
# After at depth 5, midnode will spend its own to-self output.
bitcoind.generate_block(4)
nodes[mid].wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
'OUR_UNILATERAL/DELAYED_OUTPUT_TO_US')
# The three outgoing HTLCs time out at 21, 21 and 22 blocks.
bitcoind.generate_block(16)
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
'OUR_UNILATERAL/OUR_HTLC')
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
'OUR_UNILATERAL/OUR_HTLC')
bitcoind.generate_block(1)
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
'OUR_UNILATERAL/OUR_HTLC')
# And three more for us to consider them all settled.
bitcoind.generate_block(3)
# Now, those nodes should have correctly failed the HTLCs
for n in nodes[:mid - 1]:
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE'):
n.rpc.waitsendpay(h, TIMEOUT)
# Other timeouts are 27,27,28 blocks.
bitcoind.generate_block(2)
nodes[mid].daemon.wait_for_logs(['Ignoring output.*: OUR_UNILATERAL/THEIR_HTLC'] * 2)
for _ in range(2):
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
'THEIR_UNILATERAL/OUR_HTLC')
bitcoind.generate_block(1)
nodes[mid].daemon.wait_for_log('Ignoring output.*: OUR_UNILATERAL/THEIR_HTLC')
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
'THEIR_UNILATERAL/OUR_HTLC')
# Depth 3 to consider it settled.
bitcoind.generate_block(3)
for n in nodes[mid + 1:]:
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE'):
n.rpc.waitsendpay(h, TIMEOUT)
# At depth 100 it's all done (we didn't bother waiting for mid+1's
# spends, so that might still be going)
bitcoind.generate_block(97)
nodes[mid].daemon.wait_for_logs(['onchaind complete, forgetting peer'])
# No other channels should have failed.
for i in range(len(nodes) - 1):
if i != mid:
assert only_one(nodes[i].rpc.listpeers(nodes[i + 1].info['id'])['peers'])['connected']
@pytest.mark.xfail(strict=True)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for dev_ignore_htlcs")
def test_onchain_multihtlc_their_unilateral(node_factory, bitcoind):
"""Node pushes a channel onchain with multiple HTLCs with same payment_hash """
h, nodes = setup_multihtlc_test(node_factory, bitcoind)
mid = len(nodes) // 2
for i in range(len(nodes) - 1):
assert only_one(nodes[i].rpc.listpeers(nodes[i + 1].info['id'])['peers'])['connected']
# Now midnode+1 goes onchain with midnode channel.
nodes[mid + 1].rpc.dev_fail(nodes[mid].info['id'])
nodes[mid + 1].wait_for_channel_onchain(nodes[mid].info['id'])
bitcoind.generate_block(1)
nodes[mid].daemon.wait_for_log(' to ONCHAIN')
nodes[mid + 1].daemon.wait_for_log(' to ONCHAIN')
# Now, restart and manually reconnect end nodes (so they don't ignore HTLCs)
# In fact, they'll fail them with WIRE_TEMPORARY_NODE_FAILURE.
nodes[0].restart()
nodes[-1].restart()
# We disabled auto-reconnect so we'd detect breakage, so manually reconnect.
nodes[0].rpc.connect(nodes[1].info['id'], 'localhost', nodes[1].port)
nodes[-1].rpc.connect(nodes[-2].info['id'], 'localhost', nodes[-2].port)
# Wait for HTLCs to stabilize.
nodes[0].daemon.wait_for_logs(['peer_out WIRE_UPDATE_FAIL_HTLC'] * 3)
nodes[0].daemon.wait_for_log('peer_out WIRE_COMMITMENT_SIGNED')
nodes[0].daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
nodes[-1].daemon.wait_for_logs(['peer_out WIRE_UPDATE_FAIL_HTLC'] * 3)
nodes[-1].daemon.wait_for_log('peer_out WIRE_COMMITMENT_SIGNED')
nodes[-1].daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
# At depth 5, midnode+1 will spend its own to-self output.
bitcoind.generate_block(4)
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET')
# The three outgoing HTLCs time out at depth 21, 21 and 22 blocks.
bitcoind.generate_block(16)
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
'THEIR_UNILATERAL/OUR_HTLC')
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
'THEIR_UNILATERAL/OUR_HTLC')
bitcoind.generate_block(1)
nodes[mid].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TO_US',
'THEIR_UNILATERAL/OUR_HTLC')
# At depth 3 we consider them all settled.
bitcoind.generate_block(3)
# Now, those nodes should have correctly failed the HTLCs
for n in nodes[:mid - 1]:
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE'):
n.rpc.waitsendpay(h, TIMEOUT)
# Other timeouts are at depths 27,27,28 blocks.
bitcoind.generate_block(2)
nodes[mid].daemon.wait_for_logs(['Ignoring output.*: THEIR_UNILATERAL/THEIR_HTLC'] * 2)
for _ in range(2):
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
'OUR_UNILATERAL/OUR_HTLC')
bitcoind.generate_block(1)
nodes[mid].daemon.wait_for_log('Ignoring output.*: THEIR_UNILATERAL/THEIR_HTLC')
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_HTLC_TIMEOUT_TX',
'OUR_UNILATERAL/OUR_HTLC')
# At depth 3 we consider them all settled.
bitcoind.generate_block(3)
for n in nodes[mid + 1:]:
with pytest.raises(RpcError, match=r'WIRE_PERMANENT_CHANNEL_FAILURE'):
n.rpc.waitsendpay(h, TIMEOUT)
# At depth 5, mid+1 can spend HTLC_TIMEOUT_TX output.
bitcoind.generate_block(1)
for _ in range(2):
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
'OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US')
bitcoind.generate_block(1)
nodes[mid + 1].wait_for_onchaind_broadcast('OUR_DELAYED_RETURN_TO_WALLET',
'OUR_HTLC_TIMEOUT_TX/DELAYED_OUTPUT_TO_US')
# At depth 100 they're all done.
bitcoind.generate_block(100)
nodes[mid].daemon.wait_for_logs(['onchaind complete, forgetting peer'])
nodes[mid + 1].daemon.wait_for_logs(['onchaind complete, forgetting peer'])
# No other channels should have failed.
for i in range(len(nodes) - 1):
if i != mid:
assert only_one(nodes[i].rpc.listpeers(nodes[i + 1].info['id'])['peers'])['connected']
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_permfail_htlc_in(node_factory, bitcoind, executor):
# Test case where we fail with unsettled incoming HTLC.

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