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test_lightning.py: speed up test_closing_different_fees

It was taking over 10 minutes under valgrind, causing Travis to time it out.

This shrinks it to its essential tests, and also batches.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
ppa-0.6.1
Rusty Russell 7 years ago
committed by Christian Decker
parent
commit
a497a9943d
  1. 73
      tests/test_lightningd.py

73
tests/test_lightningd.py

@ -982,38 +982,51 @@ class LightningDTests(BaseLightningDTests):
def test_closing_different_fees(self):
l1 = self.node_factory.get_node()
self.give_funds(l1, (10**6) * 5 + 1000000)
# Default feerate = 15000/7500/1000
# It will accept between upper and lower feerate, starting at normal.
for feerates in [ [ 20000, 15000, 7400 ],
[ 15000, 8000, 1000 ],
[ 15000, 6000, 1000 ],
[ 8000, 7500, 1000 ],
[ 8000, 1200, 100 ] ]:
# With and without dust
for pamount in [ 0, 545999, 546000, 546001, 10**6 // 2 ]:
l2 = self.node_factory.get_node(options=['--override-fee-rates={}/{}/{}'
.format(feerates[0],
feerates[1],
feerates[2])])
l1.rpc.connect(l2.info['id'], 'localhost', l2.info['port'])
self.fund_channel(l1, l2, 10**6)
if pamount > 0:
self.pay(l1, l2, pamount)
l1.rpc.close(l2.info['id'])
l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
l2.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIND_MUTUAL')
l2.daemon.wait_for_log(' to ONCHAIND_MUTUAL')
# It will start at the second number, accepting anything above the first.
feerates=[ [ 20000, 15000, 7400 ],
[ 8000, 1001, 100 ] ]
amounts = [ 0, 545999, 546000 ]
num_peers = len(feerates) * len(amounts)
self.give_funds(l1, (10**6) * num_peers + 10000 * num_peers)
# Create them in a batch, but only valgrind one in three, for speed!
peers = []
for feerate in feerates:
for amount in amounts:
p = self.node_factory.get_node(options=['--override-fee-rates={}/{}/{}'
.format(feerate[0],
feerate[1],
feerate[2])])
p.feerate = feerate
p.amount = amount
l1.rpc.connect(p.info['id'], 'localhost', p.info['port'])
peers.append(p)
for p in peers:
l1.rpc.fundchannel(p.info['id'], 10**6)
bitcoind.generate_block(6)
# Now wait for them all to hit normal state, do payments
for p in peers:
p.daemon.wait_for_log('to CHANNELD_NORMAL')
if p.amount != 0:
self.pay(l1,p,100000000)
# Now close
for p in peers:
l1.rpc.close(p.info['id'])
for p in peers:
p.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
bitcoind.generate_block(1)
for p in peers:
p.daemon.wait_for_log(' to ONCHAIND_MUTUAL')
l1.daemon.wait_for_logs([' to ONCHAIND_MUTUAL'] * num_peers)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_permfail(self):

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