from bitcoin.rpc import JSONRPCError from decimal import Decimal from fixtures import * # noqa: F401,F403 from fixtures import TEST_NETWORK from flaky import flaky # noqa: F401 from pyln.client import RpcError, Millisatoshi from utils import ( only_one, wait_for, sync_blockheight, EXPERIMENTAL_FEATURES, COMPAT, VALGRIND, check_coin_moves ) import os import pytest import subprocess import time import unittest @unittest.skipIf(TEST_NETWORK != 'regtest', "Test relies on a number of example addresses valid only in regtest") def test_withdraw(node_factory, bitcoind): amount = 1000000 # Don't get any funds from previous runs. l1 = node_factory.get_node(random_hsm=True) l2 = node_factory.get_node(random_hsm=True) addr = l1.rpc.newaddr()['bech32'] # Add some funds to withdraw later for i in range(10): l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10) # Reach around into the db to check that outputs were added assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 10 waddr = l1.bitcoin.rpc.getnewaddress() # Now attempt to withdraw some (making sure we collect multiple inputs) with pytest.raises(RpcError): l1.rpc.withdraw('not an address', amount) with pytest.raises(RpcError): l1.rpc.withdraw(waddr, 'not an amount') with pytest.raises(RpcError): l1.rpc.withdraw(waddr, -amount) with pytest.raises(RpcError, match=r'Cannot afford transaction'): l1.rpc.withdraw(waddr, amount * 100) out = l1.rpc.withdraw(waddr, 2 * amount) # Make sure bitcoind received the withdrawal unspent = l1.bitcoin.rpc.listunspent(0) withdrawal = [u for u in unspent if u['txid'] == out['txid']] assert(withdrawal[0]['amount'] == Decimal('0.02')) l1.bitcoin.generate_block(1) sync_blockheight(l1.bitcoin, [l1]) # Check that there are no unconfirmed outputs (change should be confirmed) for o in l1.rpc.listfunds()['outputs']: assert o['status'] == 'confirmed' # Now make sure two of them were marked as spent assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 2 # Now send some money to l2. # lightningd uses P2SH-P2WPKH waddr = l2.rpc.newaddr('bech32')['bech32'] l1.rpc.withdraw(waddr, 2 * amount) bitcoind.generate_block(1) # Make sure l2 received the withdrawal. wait_for(lambda: len(l2.rpc.listfunds()['outputs']) == 1) outputs = l2.db_query('SELECT value FROM outputs WHERE status=0;') assert only_one(outputs)['value'] == 2 * amount # Now make sure an additional two of them were marked as spent assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 4 # Simple test for withdrawal to P2WPKH # Address from: https://bc-2.jp/tools/bech32demo/index.html waddr = 'bcrt1qw508d6qejxtdg4y5r3zarvary0c5xw7kygt080' with pytest.raises(RpcError): l1.rpc.withdraw('xx1qw508d6qejxtdg4y5r3zarvary0c5xw7kxpjzsx', 2 * amount) with pytest.raises(RpcError): l1.rpc.withdraw('tb1pw508d6qejxtdg4y5r3zarvary0c5xw7kdl9fad', 2 * amount) with pytest.raises(RpcError): l1.rpc.withdraw('tb1qw508d6qejxtdg4y5r3zarvary0c5xw7kxxxxxx', 2 * amount) l1.rpc.withdraw(waddr, 2 * amount) bitcoind.generate_block(1) # Now make sure additional two of them were marked as spent assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 6 # Simple test for withdrawal to P2WSH # Address from: https://bc-2.jp/tools/bech32demo/index.html waddr = 'bcrt1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qzf4jry' with pytest.raises(RpcError): l1.rpc.withdraw('xx1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sl5k7', 2 * amount) with pytest.raises(RpcError): l1.rpc.withdraw('tb1prp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qsm03tq', 2 * amount) with pytest.raises(RpcError): l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qxxxxxx', 2 * amount) l1.rpc.withdraw(waddr, 2 * amount) bitcoind.generate_block(1) # Now make sure additional two of them were marked as spent assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 8 # failure testing for invalid SegWit addresses, from BIP173 # HRP character out of range with pytest.raises(RpcError): l1.rpc.withdraw(' 1nwldj5', 2 * amount) # overall max length exceeded with pytest.raises(RpcError): l1.rpc.withdraw('an84characterslonghumanreadablepartthatcontainsthenumber1andtheexcludedcharactersbio1569pvx', 2 * amount) # No separator character with pytest.raises(RpcError): l1.rpc.withdraw('pzry9x0s0muk', 2 * amount) # Empty HRP with pytest.raises(RpcError): l1.rpc.withdraw('1pzry9x0s0muk', 2 * amount) # Invalid witness version with pytest.raises(RpcError): l1.rpc.withdraw('BC13W508D6QEJXTDG4Y5R3ZARVARY0C5XW7KN40WF2', 2 * amount) # Invalid program length for witness version 0 (per BIP141) with pytest.raises(RpcError): l1.rpc.withdraw('BC1QR508D6QEJXTDG4Y5R3ZARVARYV98GJ9P', 2 * amount) # Mixed case with pytest.raises(RpcError): l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sL5k7', 2 * amount) # Non-zero padding in 8-to-5 conversion with pytest.raises(RpcError): l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3pjxtptv', 2 * amount) # Should have 6 outputs available. assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 6 # Test withdrawal to self. l1.rpc.withdraw(l1.rpc.newaddr('bech32')['bech32'], 'all', minconf=0) bitcoind.generate_block(1) assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 1 l1.rpc.withdraw(waddr, 'all', minconf=0) assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 0 # This should fail, can't even afford fee. with pytest.raises(RpcError, match=r'Cannot afford transaction'): l1.rpc.withdraw(waddr, 'all') # Add some funds to withdraw for i in range(12): l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 12) # Try passing in a utxo set utxos = [utxo["txid"] + ":" + str(utxo["output"]) for utxo in l1.rpc.listfunds()["outputs"]][:4] withdrawal = l1.rpc.withdraw(waddr, 2 * amount, utxos=utxos) decode = bitcoind.rpc.decoderawtransaction(withdrawal['tx']) assert decode['txid'] == withdrawal['txid'] # Check that correct utxos are included assert len(decode['vin']) == 4 vins = ["{}:{}".format(v['txid'], v['vout']) for v in decode['vin']] for utxo in utxos: assert utxo in vins # Try passing unconfirmed utxos unconfirmed_utxos = [l1.rpc.withdraw(l1.rpc.newaddr()["bech32"], 10**5) for _ in range(5)] uutxos = [u["txid"] + ":0" for u in unconfirmed_utxos] l1.rpc.withdraw(waddr, "all", minconf=0, utxos=uutxos) # Try passing minimum feerates (for relay) l1.rpc.withdraw(l1.rpc.newaddr()["bech32"], 10**5, feerate="253perkw") l1.rpc.withdraw(l1.rpc.newaddr()["bech32"], 10**5, feerate="1000perkb") def test_minconf_withdraw(node_factory, bitcoind): """Issue 2518: ensure that ridiculous confirmation levels don't overflow The number of confirmations is used to compute a maximum height that is to be accepted. If the current height is smaller than the number of confirmations we wrap around and just select everything. The fix is to clamp the maxheight parameter to a positive small number. """ amount = 1000000 # Don't get any funds from previous runs. l1 = node_factory.get_node(random_hsm=True) addr = l1.rpc.newaddr()['bech32'] # Add some funds to withdraw later for i in range(10): l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10) with pytest.raises(RpcError): l1.rpc.withdraw(destination=addr, satoshi=10000, feerate='normal', minconf=9999999) def test_addfunds_from_block(node_factory, bitcoind): """Send funds to the daemon without telling it explicitly """ # Previous runs with same bitcoind can leave funds! l1 = node_factory.get_node(random_hsm=True) addr = l1.rpc.newaddr()['bech32'] bitcoind.rpc.sendtoaddress(addr, 0.1) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 1) outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert only_one(outputs)['value'] == 10000000 # The address we detect must match what was paid to. output = only_one(l1.rpc.listfunds()['outputs']) assert output['address'] == addr # Send all our money to a P2WPKH address this time. addr = l1.rpc.newaddr("bech32")['bech32'] l1.rpc.withdraw(addr, "all") bitcoind.generate_block(1) time.sleep(1) # The address we detect must match what was paid to. output = only_one(l1.rpc.listfunds()['outputs']) assert output['address'] == addr @unittest.skipIf(not COMPAT, "needs COMPAT=1") def test_deprecated_txprepare(node_factory, bitcoind): """Test the deprecated old-style: txprepare {destination} {satoshi} {feerate} {minconf} """ amount = 10**4 l1 = node_factory.get_node(options={'allow-deprecated-apis': True}) addr = l1.rpc.newaddr()['bech32'] for i in range(7): l1.fundwallet(10**8) bitcoind.generate_block(1) sync_blockheight(bitcoind, [l1]) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 7) # Array type with pytest.raises(RpcError, match=r'.* should be an amount in satoshis or all, not .*'): l1.rpc.call('txprepare', [addr, 'slow']) with pytest.raises(RpcError, match=r'Need set \'satoshi\' field.'): l1.rpc.call('txprepare', [addr]) with pytest.raises(RpcError, match=r'Could not parse destination address.*'): l1.rpc.call('txprepare', [Millisatoshi(amount * 100), 'slow', 1]) l1.rpc.call('txprepare', [addr, Millisatoshi(amount * 100), 'slow', 1]) l1.rpc.call('txprepare', [addr, Millisatoshi(amount * 100), 'normal']) l1.rpc.call('txprepare', [addr, Millisatoshi(amount * 100), None, 1]) l1.rpc.call('txprepare', [addr, Millisatoshi(amount * 100)]) # Object type with pytest.raises(RpcError, match=r'Need set \'outputs\' field.'): l1.rpc.call('txprepare', {'destination': addr, 'feerate': 'slow'}) with pytest.raises(RpcError, match=r'Need set \'outputs\' field.'): l1.rpc.call('txprepare', {'satoshi': Millisatoshi(amount * 100), 'feerate': '10perkw', 'minconf': 2}) l1.rpc.call('txprepare', {'destination': addr, 'satoshi': Millisatoshi(amount * 100), 'feerate': '2000perkw', 'minconf': 1}) l1.rpc.call('txprepare', {'destination': addr, 'satoshi': Millisatoshi(amount * 100), 'feerate': '2000perkw'}) l1.rpc.call('txprepare', {'destination': addr, 'satoshi': Millisatoshi(amount * 100)}) def test_txprepare_multi(node_factory, bitcoind): amount = 10000000 l1 = node_factory.get_node(random_hsm=True) bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 1) outputs = [] for i in range(9): outputs.append({l1.rpc.newaddr()['bech32']: Millisatoshi(amount * 100)}) prep = l1.rpc.txprepare(outputs=outputs) l1.rpc.txdiscard(prep['txid']) def test_txprepare(node_factory, bitcoind, chainparams): amount = 1000000 l1 = node_factory.get_node(random_hsm=True) addr = chainparams['example_addr'] # Add some funds to withdraw later: both bech32 and p2sh for i in range(5): bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8) bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'], amount / 10**8) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10) prep = l1.rpc.txprepare(outputs=[{addr: Millisatoshi(amount * 3 * 1000)}]) assert prep['psbt'] decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx']) assert decode['txid'] == prep['txid'] # 4 inputs, 2 outputs (3 if we have a fee output). assert len(decode['vin']) == 4 assert len(decode['vout']) == 2 if not chainparams['feeoutput'] else 3 # One output will be correct. outnum = [i for i, o in enumerate(decode['vout']) if o['value'] == Decimal(amount * 3) / 10**8][0] for i, o in enumerate(decode['vout']): if i == outnum: assert o['scriptPubKey']['type'] == 'witness_v0_keyhash' assert o['scriptPubKey']['addresses'] == [addr] else: assert o['scriptPubKey']['type'] in ['witness_v0_keyhash', 'fee'] # Now prepare one with no change. prep2 = l1.rpc.txprepare([{addr: 'all'}]) decode = bitcoind.rpc.decoderawtransaction(prep2['unsigned_tx']) assert decode['txid'] == prep2['txid'] # 6 inputs, 1 outputs. assert len(decode['vin']) == 6 assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2 # Some fees will be paid. assert decode['vout'][0]['value'] < Decimal(amount * 6) / 10**8 assert decode['vout'][0]['value'] > Decimal(amount * 6) / 10**8 - Decimal(0.0002) assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash' assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr] # If I cancel the first one, I can get those first 4 outputs. discard = l1.rpc.txdiscard(prep['txid']) assert discard['txid'] == prep['txid'] assert discard['unsigned_tx'] == prep['unsigned_tx'] prep3 = l1.rpc.txprepare([{addr: 'all'}]) decode = bitcoind.rpc.decoderawtransaction(prep3['unsigned_tx']) assert decode['txid'] == prep3['txid'] # 4 inputs, 1 outputs. assert len(decode['vin']) == 4 assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2 # Some fees will be taken assert decode['vout'][0]['value'] < Decimal(amount * 4) / 10**8 assert decode['vout'][0]['value'] > Decimal(amount * 4) / 10**8 - Decimal(0.0002) assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash' assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr] # Cannot discard twice. with pytest.raises(RpcError, match=r'not an unreleased txid'): l1.rpc.txdiscard(prep['txid']) # Discard everything, we should now spend all inputs. l1.rpc.txdiscard(prep2['txid']) l1.rpc.txdiscard(prep3['txid']) prep4 = l1.rpc.txprepare([{addr: 'all'}]) decode = bitcoind.rpc.decoderawtransaction(prep4['unsigned_tx']) assert decode['txid'] == prep4['txid'] # 10 inputs, 1 outputs. assert len(decode['vin']) == 10 assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2 # Some fees will be taken assert decode['vout'][0]['value'] < Decimal(amount * 10) / 10**8 assert decode['vout'][0]['value'] > Decimal(amount * 10) / 10**8 - Decimal(0.0003) assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash' assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr] l1.rpc.txdiscard(prep4['txid']) # Try passing in a utxo set utxos = [utxo["txid"] + ":" + str(utxo["output"]) for utxo in l1.rpc.listfunds()["outputs"]][:4] prep5 = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3.5 * 1000)}], utxos=utxos) # Try passing unconfirmed utxos unconfirmed_utxo = l1.rpc.withdraw(l1.rpc.newaddr()["bech32"], 10**5) uutxos = [unconfirmed_utxo["txid"] + ":0"] with pytest.raises(RpcError, match=r"Cannot afford transaction .* use " "confirmed utxos."): l1.rpc.txprepare([{addr: Millisatoshi(amount * 3.5 * 1000)}], utxos=uutxos) decode = bitcoind.rpc.decoderawtransaction(prep5['unsigned_tx']) assert decode['txid'] == prep5['txid'] # Check that correct utxos are included assert len(decode['vin']) == 4 vins = ["{}:{}".format(v['txid'], v['vout']) for v in decode['vin']] for utxo in utxos: assert utxo in vins # We should have a change output, so this is exact assert len(decode['vout']) == 3 if chainparams['feeoutput'] else 2 assert decode['vout'][1]['value'] == Decimal(amount * 3.5) / 10**8 assert decode['vout'][1]['scriptPubKey']['type'] == 'witness_v0_keyhash' assert decode['vout'][1]['scriptPubKey']['addresses'] == [addr] # Discard prep4 and get all funds again l1.rpc.txdiscard(prep5['txid']) with pytest.raises(RpcError, match=r'this destination wants all satoshi. The count of outputs can\'t be more than 1'): prep5 = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 1000)}, {addr: 'all'}]) prep5 = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 500 + 100000)}, {addr: Millisatoshi(amount * 3 * 500 - 100000)}]) decode = bitcoind.rpc.decoderawtransaction(prep5['unsigned_tx']) assert decode['txid'] == prep5['txid'] # 4 inputs, 3 outputs(include change). assert len(decode['vin']) == 4 assert len(decode['vout']) == 4 if chainparams['feeoutput'] else 3 # One output will be correct. for i in range(3 + chainparams['feeoutput']): if decode['vout'][i - 1]['value'] == Decimal('0.01500100'): outnum1 = i - 1 elif decode['vout'][i - 1]['value'] == Decimal('0.01499900'): outnum2 = i - 1 else: changenum = i - 1 assert decode['vout'][outnum1]['scriptPubKey']['type'] == 'witness_v0_keyhash' assert decode['vout'][outnum1]['scriptPubKey']['addresses'] == [addr] assert decode['vout'][outnum2]['scriptPubKey']['type'] == 'witness_v0_keyhash' assert decode['vout'][outnum2]['scriptPubKey']['addresses'] == [addr] assert decode['vout'][changenum]['scriptPubKey']['type'] == 'witness_v0_keyhash' def test_reserveinputs(node_factory, bitcoind, chainparams): """ Reserve inputs is basically the same as txprepare, with the slight exception that 'reserveinputs' doesn't keep the unsent transaction around """ amount = 1000000 total_outs = 12 l1 = node_factory.get_node(feerates=(7500, 7500, 7500, 7500)) addr = chainparams['example_addr'] # Add a medley of funds to withdraw later, bech32 + p2sh-p2wpkh for i in range(total_outs // 2): bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8) bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'], amount / 10**8) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == total_outs) utxo_count = 8 sent = Decimal('0.01') * (utxo_count - 1) reserved = l1.rpc.reserveinputs(outputs=[{addr: Millisatoshi(amount * (utxo_count - 1) * 1000)}]) assert reserved['feerate_per_kw'] == 7500 psbt = bitcoind.rpc.decodepsbt(reserved['psbt']) out_found = False assert len(psbt['inputs']) == utxo_count outputs = l1.rpc.listfunds()['outputs'] assert len([x for x in outputs if not x['reserved']]) == total_outs - utxo_count assert len([x for x in outputs if x['reserved']]) == utxo_count total_outs -= utxo_count saved_input = psbt['tx']['vin'][0] # We should have two outputs for vout in psbt['tx']['vout']: if vout['scriptPubKey']['addresses'][0] == addr: assert vout['value'] == sent out_found = True assert out_found # Do it again, but for too many inputs utxo_count = 12 - utxo_count + 1 sent = Decimal('0.01') * (utxo_count - 1) with pytest.raises(RpcError, match=r"Cannot afford transaction"): reserved = l1.rpc.reserveinputs(outputs=[{addr: Millisatoshi(amount * (utxo_count - 1) * 1000)}]) utxo_count -= 1 sent = Decimal('0.01') * (utxo_count - 1) reserved = l1.rpc.reserveinputs(outputs=[{addr: Millisatoshi(amount * (utxo_count - 1) * 1000)}], feerate='10000perkw') assert reserved['feerate_per_kw'] == 10000 psbt = bitcoind.rpc.decodepsbt(reserved['psbt']) assert len(psbt['inputs']) == utxo_count outputs = l1.rpc.listfunds()['outputs'] assert len([x for x in outputs if not x['reserved']]) == total_outs - utxo_count == 0 assert len([x for x in outputs if x['reserved']]) == 12 # No more available with pytest.raises(RpcError, match=r"Cannot afford transaction"): reserved = l1.rpc.reserveinputs(outputs=[{addr: Millisatoshi(amount * 1)}], feerate='253perkw') # Unreserve three, from different psbts unreserve_utxos = [ { 'txid': saved_input['txid'], 'vout': saved_input['vout'], 'sequence': saved_input['sequence'] }, { 'txid': psbt['tx']['vin'][0]['txid'], 'vout': psbt['tx']['vin'][0]['vout'], 'sequence': psbt['tx']['vin'][0]['sequence'] }, { 'txid': psbt['tx']['vin'][1]['txid'], 'vout': psbt['tx']['vin'][1]['vout'], 'sequence': psbt['tx']['vin'][1]['sequence'] }] unreserve_psbt = bitcoind.rpc.createpsbt(unreserve_utxos, []) unreserved = l1.rpc.unreserveinputs(unreserve_psbt) assert all([x['unreserved'] for x in unreserved['outputs']]) outputs = l1.rpc.listfunds()['outputs'] assert len([x for x in outputs if not x['reserved']]) == len(unreserved['outputs']) for i in range(len(unreserved['outputs'])): un = unreserved['outputs'][i] u_utxo = unreserve_utxos[i] assert un['txid'] == u_utxo['txid'] and un['vout'] == u_utxo['vout'] and un['unreserved'] # Try unreserving the same utxos again, plus one that's not included # We expect this to be a no-op. unreserve_utxos.append({'txid': 'b' * 64, 'vout': 0, 'sequence': 0}) unreserve_psbt = bitcoind.rpc.createpsbt(unreserve_utxos, []) unreserved = l1.rpc.unreserveinputs(unreserve_psbt) assert not any([x['unreserved'] for x in unreserved['outputs']]) for un in unreserved['outputs']: assert not un['unreserved'] assert len([x for x in l1.rpc.listfunds()['outputs'] if not x['reserved']]) == 3 # passing in an empty string should fail with pytest.raises(RpcError, match=r"should be a PSBT, not "): l1.rpc.unreserveinputs('') # reserve one of the utxos that we just unreserved utxos = [] utxos.append(saved_input['txid'] + ":" + str(saved_input['vout'])) reserved = l1.rpc.reserveinputs([{addr: Millisatoshi(amount * 0.5 * 1000)}], feerate='253perkw', utxos=utxos) assert len([x for x in l1.rpc.listfunds()['outputs'] if not x['reserved']]) == 2 psbt = bitcoind.rpc.decodepsbt(reserved['psbt']) assert len(psbt['inputs']) == 1 vin = psbt['tx']['vin'][0] assert vin['txid'] == saved_input['txid'] and vin['vout'] == saved_input['vout'] # reserve them all! reserved = l1.rpc.reserveinputs([{addr: 'all'}]) outputs = l1.rpc.listfunds()['outputs'] assert len([x for x in outputs if not x['reserved']]) == 0 assert len([x for x in outputs if x['reserved']]) == 12 # FIXME: restart the node, nothing will remain reserved l1.restart() assert len(l1.rpc.listfunds()['outputs']) == 12 def test_sign_and_send_psbt(node_factory, bitcoind, chainparams): """ Tests for the sign + send psbt RPCs """ amount = 1000000 total_outs = 12 coin_mvt_plugin = os.path.join(os.getcwd(), 'tests/plugins/coin_movements.py') l1 = node_factory.get_node(options={'plugin': coin_mvt_plugin}, feerates=(7500, 7500, 7500, 7500)) l2 = node_factory.get_node() addr = chainparams['example_addr'] # Add a medley of funds to withdraw later, bech32 + p2sh-p2wpkh for i in range(total_outs // 2): bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8) bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'], amount / 10**8) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == total_outs) # Make a PSBT out of our inputs reserved = l1.rpc.reserveinputs(outputs=[{addr: Millisatoshi(3 * amount * 1000)}]) assert len([x for x in l1.rpc.listfunds()['outputs'] if x['reserved']]) == 4 psbt = bitcoind.rpc.decodepsbt(reserved['psbt']) saved_input = psbt['tx']['vin'][0] # Go ahead and unreserve the UTXOs, we'll use a smaller # set of them to create a second PSBT that we'll attempt to sign # and broadcast (to disastrous results) l1.rpc.unreserveinputs(reserved['psbt']) # Re-reserve one of the utxos we just unreserved utxos = [] utxos.append(saved_input['txid'] + ":" + str(saved_input['vout'])) second_reservation = l1.rpc.reserveinputs([{addr: Millisatoshi(amount * 0.5 * 1000)}], feerate='253perkw', utxos=utxos) # We require the utxos be reserved before signing them with pytest.raises(RpcError, match=r"Aborting PSBT signing. UTXO .* is not reserved"): l1.rpc.signpsbt(reserved['psbt'])['signed_psbt'] # Now we unreserve the singleton, so we can reserve it again l1.rpc.unreserveinputs(second_reservation['psbt']) # We re-reserve the first set... utxos = [] for vin in psbt['tx']['vin']: utxos.append(vin['txid'] + ':' + str(vin['vout'])) reserved = l1.rpc.reserveinputs(outputs=[{addr: Millisatoshi(3 * amount * 1000)}], utxos=utxos) # Sign + send the PSBT we've created signed_psbt = l1.rpc.signpsbt(reserved['psbt'])['signed_psbt'] broadcast_tx = l1.rpc.sendpsbt(signed_psbt) # Check that it was broadcast successfully l1.daemon.wait_for_log(r'sendrawtx exit 0 .* sendrawtransaction {}'.format(broadcast_tx['tx'])) bitcoind.generate_block(1) # We expect a change output to be added to the wallet expected_outs = total_outs - 4 + 1 wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == expected_outs) # Let's try *sending* a PSBT that can't be finalized (it's unsigned) with pytest.raises(RpcError, match=r"PSBT not finalizeable"): l1.rpc.sendpsbt(second_reservation['psbt']) # Now we try signing a PSBT with an output that's already been spent with pytest.raises(RpcError, match=r"Aborting PSBT signing. UTXO {} is not reserved".format(utxos[0])): l1.rpc.signpsbt(second_reservation['psbt']) # Queue up another node, to make some PSBTs for us for i in range(total_outs // 2): bitcoind.rpc.sendtoaddress(l2.rpc.newaddr()['bech32'], amount / 10**8) bitcoind.rpc.sendtoaddress(l2.rpc.newaddr('p2sh-segwit')['p2sh-segwit'], amount / 10**8) # Create a PSBT using L2 bitcoind.generate_block(1) wait_for(lambda: len(l2.rpc.listfunds()['outputs']) == total_outs) l2_reserved = l2.rpc.reserveinputs(outputs=[{addr: Millisatoshi(3 * amount * 1000)}]) # Try to get L1 to sign it with pytest.raises(RpcError, match=r"No wallet inputs to sign"): l1.rpc.signpsbt(l2_reserved['psbt']) # Add some of our own PSBT inputs to it l1_reserved = l1.rpc.reserveinputs(outputs=[{addr: Millisatoshi(3 * amount * 1000)}]) joint_psbt = bitcoind.rpc.joinpsbts([l1_reserved['psbt'], l2_reserved['psbt']]) half_signed_psbt = l1.rpc.signpsbt(joint_psbt)['signed_psbt'] totally_signed = l2.rpc.signpsbt(half_signed_psbt)['signed_psbt'] broadcast_tx = l1.rpc.sendpsbt(totally_signed) l1.daemon.wait_for_log(r'sendrawtx exit 0 .* sendrawtransaction {}'.format(broadcast_tx['tx'])) # Send a PSBT that's not ours l2_reserved = l2.rpc.reserveinputs(outputs=[{addr: Millisatoshi(3 * amount * 1000)}]) l2_signed_psbt = l2.rpc.signpsbt(l2_reserved['psbt'])['signed_psbt'] l1.rpc.sendpsbt(l2_signed_psbt) # Re-try sending the same tx? bitcoind.generate_block(1) sync_blockheight(bitcoind, [l1]) # Expect an error here with pytest.raises(JSONRPCError, match=r"Transaction already in block chain"): bitcoind.rpc.sendrawtransaction(broadcast_tx['tx']) # Try an empty PSBT with pytest.raises(RpcError, match=r"should be a PSBT, not"): l1.rpc.signpsbt('') with pytest.raises(RpcError, match=r"should be a PSBT, not"): l1.rpc.sendpsbt('') # Try a modified (invalid) PSBT string modded_psbt = l2_reserved['psbt'][:-3] + 'A' + l2_reserved['psbt'][-3:] with pytest.raises(RpcError, match=r"should be a PSBT, not"): l1.rpc.signpsbt(modded_psbt) wallet_coin_mvts = [ {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 1000000000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'spend_track'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'spend_track'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'spend_track'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'spend_track'}, # Nicely splits out withdrawals and chain fees, because it's all our tx {'type': 'chain_mvt', 'credit': 0, 'debit': 988255000, 'tag': 'withdrawal'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 3000000000, 'tag': 'withdrawal'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 11745000, 'tag': 'chain_fees'}, {'type': 'chain_mvt', 'credit': 988255000, 'debit': 0, 'tag': 'deposit'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'spend_track'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'spend_track'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'spend_track'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'spend_track'}, # Note that this is technically wrong since we paid 11745sat in fees # but since it includes inputs / outputs from a second node, we can't # do proper acccounting for it. {'type': 'chain_mvt', 'credit': 0, 'debit': 4000000000, 'tag': 'withdrawal'}, {'type': 'chain_mvt', 'credit': 0, 'debit': 0, 'tag': 'chain_fees'}, {'type': 'chain_mvt', 'credit': 988285000, 'debit': 0, 'tag': 'deposit'}, ] check_coin_moves(l1, 'wallet', wallet_coin_mvts, chainparams) def test_txsend(node_factory, bitcoind, chainparams): amount = 1000000 l1 = node_factory.get_node(random_hsm=True) addr = chainparams['example_addr'] # Add some funds to withdraw later: both bech32 and p2sh for i in range(5): bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8) bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'], amount / 10**8) bitcoind.generate_block(1) wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10) prep = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 1000)}]) out = l1.rpc.txsend(prep['txid']) # Cannot discard after send! with pytest.raises(RpcError, match=r'not an unreleased txid'): l1.rpc.txdiscard(prep['txid']) wait_for(lambda: prep['txid'] in bitcoind.rpc.getrawmempool()) # Signed tx should have same txid decode = bitcoind.rpc.decoderawtransaction(out['tx']) assert decode['txid'] == prep['txid'] bitcoind.generate_block(1) # Change output should appear. if decode['vout'][0]['value'] == Decimal(amount * 3) / 10**8: changenum = 1 elif decode['vout'][1]['value'] == Decimal(amount * 3) / 10**8: changenum = 0 else: assert False # Those spent outputs are gone, but change output has arrived. wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10 - len(decode['vin']) + 1) # Change address should appear in listfunds() assert decode['vout'][changenum]['scriptPubKey']['addresses'][0] in [f['address'] for f in l1.rpc.listfunds()['outputs']] def test_txprepare_restart(node_factory, bitcoind, chainparams): amount = 1000000 l1 = node_factory.get_node(may_fail=True) addr = chainparams['example_addr'] # Add some funds to withdraw later: both bech32 and p2sh for i in range(5): bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8) bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'], amount / 10**8) bitcoind.generate_block(1) wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10) prep = l1.rpc.txprepare([{addr: 'all'}]) decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx']) assert decode['txid'] == prep['txid'] # All 10 inputs assert len(decode['vin']) == 10 # L1 will forget all about it. l1.restart() # It goes backwards in blockchain just in case there was a reorg. Wait. wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10) with pytest.raises(RpcError, match=r'not an unreleased txid'): l1.rpc.txdiscard(prep['txid']) prep = l1.rpc.txprepare([{addr: 'all'}]) decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx']) assert decode['txid'] == prep['txid'] # All 10 inputs assert len(decode['vin']) == 10 # This will also work if we simply kill it. l1.restart(clean=False) # It goes backwards in blockchain just in case there was a reorg. Wait. wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10) # It should have logged this for each output (any order) template = r'wallet: reserved output {}/{} reset to available' lines = [template.format(i['txid'], i['vout']) for i in decode['vin']] l1.daemon.wait_for_logs(lines) prep = l1.rpc.txprepare([{addr: 'all'}]) decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx']) assert decode['txid'] == prep['txid'] # All 10 inputs assert len(decode['vin']) == 10 @unittest.skipIf(TEST_NETWORK != 'regtest', "Fee outputs throw off our output matching logic") @unittest.skipIf(not EXPERIMENTAL_FEATURES, "Tests annotations which are compiled only with experimental features") def test_transaction_annotations(node_factory, bitcoind): l1, l2, l3 = node_factory.get_nodes(3) l1.fundwallet(10**6) # We should now have a transaction that gave us the funds in the # transactions table... outputs = l1.rpc.listfunds()['outputs'] assert(len(outputs) == 1 and outputs[0]['status'] == 'confirmed') out = outputs[0] idx = out['output'] assert(idx in [0, 1] and out['value'] == 10**6) # ... and it should have an annotation on the output reading 'deposit' txs = l1.rpc.listtransactions()['transactions'] assert(len(txs) == 1) tx = txs[0] output = tx['outputs'][idx] assert(output['type'] == 'deposit' and output['satoshis'] == '1000000000msat') # ... and all other output should be change, and have no annotations types = [] for i, o in enumerate(tx['outputs']): if i == idx: continue if 'type' in o: types.append(o['type']) else: types.append(None) assert(set([None]) == set(types)) ########################################################################## # Let's now open a channel. The opener should get the funding transaction # annotated as channel open and deposit. l1.connect(l2) fundingtx = l1.rpc.fundchannel(l2.info['id'], 10**5) # We should have one output available, and it should be unconfirmed outputs = l1.rpc.listfunds()['outputs'] assert(len(outputs) == 1 and outputs[0]['status'] == 'unconfirmed') # It should also match the funding txid: assert(outputs[0]['txid'] == fundingtx['txid']) # Confirm the channel and check that the output changed to confirmed bitcoind.generate_block(3) sync_blockheight(bitcoind, [l1, l2]) outputs = l1.rpc.listfunds()['outputs'] assert(len(outputs) == 1 and outputs[0]['status'] == 'confirmed') # We should have 2 transactions, the second one should be the funding tx # (we are ordering by blockheight and txindex, so that order should be ok) txs = l1.rpc.listtransactions()['transactions'] assert(len(txs) == 2 and txs[1]['hash'] == fundingtx['txid']) # Check the annotated types types = [o['type'] for o in txs[1]['outputs']] changeidx = 0 if types[0] == 'deposit' else 1 fundidx = 1 - changeidx assert(types[changeidx] == 'deposit' and types[fundidx] == 'channel_funding') # And check the channel annotation on the funding output peers = l1.rpc.listpeers()['peers'] assert(len(peers) == 1 and len(peers[0]['channels']) == 1) scid = peers[0]['channels'][0]['short_channel_id'] assert(txs[1]['outputs'][fundidx]['channel'] == scid) @unittest.skipIf(VALGRIND, "It does not play well with prompt and key derivation.") def test_hsm_secret_encryption(node_factory): l1 = node_factory.get_node(may_fail=True) # May fail when started without key password = "reckful\n" # We need to simulate a terminal to use termios in `lightningd`. master_fd, slave_fd = os.openpty() # Test we can encrypt an already-existing and not encrypted hsm_secret l1.stop() l1.daemon.opts.update({"encrypted-hsm": None}) l1.daemon.start(stdin=slave_fd, wait_for_initialized=False) l1.daemon.wait_for_log(r'The hsm_secret is encrypted') os.write(master_fd, password.encode("utf-8")) l1.daemon.wait_for_log("Server started with public key") id = l1.rpc.getinfo()["id"] l1.stop() # Test we cannot start the same wallet without specifying --encrypted-hsm l1.daemon.opts.pop("encrypted-hsm") with pytest.raises(subprocess.CalledProcessError, match=r'returned non-zero exit status 1'): subprocess.check_call(l1.daemon.cmd_line) # Test we cannot restore the same wallet with another password l1.daemon.opts.update({"encrypted-hsm": None}) l1.daemon.start(stdin=slave_fd, stderr=subprocess.STDOUT, wait_for_initialized=False) l1.daemon.wait_for_log(r'The hsm_secret is encrypted') os.write(master_fd, password[2:].encode("utf-8")) assert(l1.daemon.proc.wait() == 1) assert(l1.daemon.is_in_log("Wrong password for encrypted hsm_secret.")) # Test we can restore the same wallet with the same password l1.daemon.start(stdin=slave_fd, wait_for_initialized=False) l1.daemon.wait_for_log(r'The hsm_secret is encrypted') os.write(master_fd, password.encode("utf-8")) l1.daemon.wait_for_log("Server started with public key") assert id == l1.rpc.getinfo()["id"] @unittest.skipIf(VALGRIND, "It does not play well with prompt and key derivation.") def test_hsmtool_secret_decryption(node_factory): l1 = node_factory.get_node() password = "reckless\n" hsm_path = os.path.join(l1.daemon.lightning_dir, TEST_NETWORK, "hsm_secret") # We need to simulate a terminal to use termios in `lightningd`. master_fd, slave_fd = os.openpty() # Encrypt the master seed l1.stop() l1.daemon.opts.update({"encrypted-hsm": None}) l1.daemon.start(stdin=slave_fd, wait_for_initialized=False) l1.daemon.wait_for_log(r'The hsm_secret is encrypted') os.write(master_fd, password.encode("utf-8")) l1.daemon.wait_for_log("Server started with public key") node_id = l1.rpc.getinfo()["id"] l1.stop() # We can't use a wrong password ! cmd_line = ["tools/hsmtool", "decrypt", hsm_path, "A wrong pass"] with pytest.raises(subprocess.CalledProcessError): subprocess.check_call(cmd_line) # Decrypt it with hsmtool cmd_line[3] = password[:-1] subprocess.check_call(cmd_line) # Then test we can now start it without password l1.daemon.opts.pop("encrypted-hsm") l1.daemon.start(stdin=slave_fd, wait_for_initialized=True) assert node_id == l1.rpc.getinfo()["id"] l1.stop() # Test we can encrypt it offline cmd_line[1] = "encrypt" subprocess.check_call(cmd_line) # Now we need to pass the encrypted-hsm startup option l1.stop() with pytest.raises(subprocess.CalledProcessError, match=r'returned non-zero exit status 1'): subprocess.check_call(l1.daemon.cmd_line) l1.daemon.opts.update({"encrypted-hsm": None}) master_fd, slave_fd = os.openpty() l1.daemon.start(stdin=slave_fd, stderr=subprocess.STDOUT, wait_for_initialized=False) l1.daemon.wait_for_log(r'The hsm_secret is encrypted') os.write(master_fd, password.encode("utf-8")) l1.daemon.wait_for_log("Server started with public key") assert node_id == l1.rpc.getinfo()["id"] l1.stop() # And finally test that we can also decrypt if encrypted with hsmtool cmd_line[1] = "decrypt" subprocess.check_call(cmd_line) l1.daemon.opts.pop("encrypted-hsm") l1.daemon.start(stdin=slave_fd, wait_for_initialized=True) assert node_id == l1.rpc.getinfo()["id"] # this test does a 'listtransactions' on a yet unconfirmed channel def test_fundchannel_listtransaction(node_factory, bitcoind): l1, l2 = node_factory.get_nodes(2) l1.fundwallet(10**6) l1.connect(l2) txid = l1.rpc.fundchannel(l2.info['id'], 10**5)['txid'] # next call warned about SQL Accessing a null column # and crashed the daemon for accessing random memory or null txs = l1.rpc.listtransactions()['transactions'] tx = [t for t in txs if t['hash'] == txid][0] assert tx['blockheight'] == 0 def test_withdraw_nlocktime(node_factory): """ Test that we don't set the nLockTime to 0 for withdrawal and txprepare transactions. """ l1 = node_factory.get_node(1) l1.fundwallet(10**4) l1.fundwallet(10**4) # withdraw addr = l1.rpc.newaddr()["bech32"] tx = l1.rpc.withdraw(addr, 10**3)["tx"] nlocktime = node_factory.bitcoind.rpc.decoderawtransaction(tx)["locktime"] tip = node_factory.bitcoind.rpc.getblockcount() assert nlocktime > 0 and nlocktime <= tip # txprepare txid = l1.rpc.txprepare([{addr: 10**3}])["txid"] tx = l1.rpc.txsend(txid)["tx"] nlocktime = node_factory.bitcoind.rpc.decoderawtransaction(tx)["locktime"] tip = node_factory.bitcoind.rpc.getblockcount() assert nlocktime > 0 and nlocktime <= tip @flaky @unittest.skipIf(VALGRIND, "A big loop is used to check fuzz.") def test_withdraw_nlocktime_fuzz(node_factory, bitcoind): """ Test that we eventually fuzz nLockTime for withdrawal transactions. Marked flaky "just in case" as we fuzz from 0 to 100 with a 10% probability. """ l1 = node_factory.get_node(1) l1.fundwallet(10**8) for i in range(100): addr = l1.rpc.newaddr()["bech32"] withdraw = l1.rpc.withdraw(addr, 10**3) bitcoind.generate_block(1) l1.daemon.wait_for_log('Owning output .* txid {} CONFIRMED'. format(withdraw["txid"])) decoded = bitcoind.rpc.decoderawtransaction(withdraw["tx"]) tip = node_factory.bitcoind.rpc.getblockcount() assert decoded["locktime"] > 0 if decoded["locktime"] < tip: return else: raise Exception("No transaction with fuzzed nLockTime !")