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450 lines
18 KiB
450 lines
18 KiB
from decimal import Decimal
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from fixtures import * # noqa: F401,F403
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from fixtures import TEST_NETWORK
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from flaky import flaky # noqa: F401
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from lightning import RpcError, Millisatoshi
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from utils import only_one, wait_for, sync_blockheight
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import pytest
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import time
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import unittest
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@unittest.skipIf(TEST_NETWORK != 'regtest', "Test relies on a number of example addresses valid only in regtest")
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def test_withdraw(node_factory, bitcoind):
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amount = 1000000
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# Don't get any funds from previous runs.
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l1 = node_factory.get_node(random_hsm=True)
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l2 = node_factory.get_node(random_hsm=True)
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addr = l1.rpc.newaddr()['bech32']
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# Add some funds to withdraw later
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for i in range(10):
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l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01)
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bitcoind.generate_block(1)
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wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)
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# Reach around into the db to check that outputs were added
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assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 10
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waddr = l1.bitcoin.rpc.getnewaddress()
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# Now attempt to withdraw some (making sure we collect multiple inputs)
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with pytest.raises(RpcError):
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l1.rpc.withdraw('not an address', amount)
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with pytest.raises(RpcError):
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l1.rpc.withdraw(waddr, 'not an amount')
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with pytest.raises(RpcError):
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l1.rpc.withdraw(waddr, -amount)
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with pytest.raises(RpcError, match=r'Cannot afford transaction'):
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l1.rpc.withdraw(waddr, amount * 100)
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out = l1.rpc.withdraw(waddr, 2 * amount)
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# Make sure bitcoind received the withdrawal
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unspent = l1.bitcoin.rpc.listunspent(0)
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withdrawal = [u for u in unspent if u['txid'] == out['txid']]
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assert(withdrawal[0]['amount'] == Decimal('0.02'))
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l1.bitcoin.generate_block(1)
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sync_blockheight(l1.bitcoin, [l1])
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# Check that there are no unconfirmed outputs (change should be confirmed)
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for o in l1.rpc.listfunds()['outputs']:
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assert o['status'] == 'confirmed'
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# Now make sure two of them were marked as spent
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assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 2
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# Now send some money to l2.
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# lightningd uses P2SH-P2WPKH
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waddr = l2.rpc.newaddr('bech32')['bech32']
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l1.rpc.withdraw(waddr, 2 * amount)
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bitcoind.generate_block(1)
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# Make sure l2 received the withdrawal.
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wait_for(lambda: len(l2.rpc.listfunds()['outputs']) == 1)
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outputs = l2.db_query('SELECT value FROM outputs WHERE status=0;')
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assert only_one(outputs)['value'] == 2 * amount
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# Now make sure an additional two of them were marked as spent
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assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 4
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# Simple test for withdrawal to P2WPKH
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# Address from: https://bc-2.jp/tools/bech32demo/index.html
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waddr = 'bcrt1qw508d6qejxtdg4y5r3zarvary0c5xw7kygt080'
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with pytest.raises(RpcError):
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l1.rpc.withdraw('xx1qw508d6qejxtdg4y5r3zarvary0c5xw7kxpjzsx', 2 * amount)
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with pytest.raises(RpcError):
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l1.rpc.withdraw('tb1pw508d6qejxtdg4y5r3zarvary0c5xw7kdl9fad', 2 * amount)
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with pytest.raises(RpcError):
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l1.rpc.withdraw('tb1qw508d6qejxtdg4y5r3zarvary0c5xw7kxxxxxx', 2 * amount)
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l1.rpc.withdraw(waddr, 2 * amount)
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bitcoind.generate_block(1)
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# Now make sure additional two of them were marked as spent
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assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 6
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# Simple test for withdrawal to P2WSH
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# Address from: https://bc-2.jp/tools/bech32demo/index.html
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waddr = 'bcrt1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qzf4jry'
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with pytest.raises(RpcError):
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l1.rpc.withdraw('xx1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sl5k7', 2 * amount)
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with pytest.raises(RpcError):
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l1.rpc.withdraw('tb1prp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qsm03tq', 2 * amount)
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with pytest.raises(RpcError):
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l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3qxxxxxx', 2 * amount)
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l1.rpc.withdraw(waddr, 2 * amount)
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bitcoind.generate_block(1)
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# Now make sure additional two of them were marked as spent
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assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=2')[0]['c'] == 8
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# failure testing for invalid SegWit addresses, from BIP173
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# HRP character out of range
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with pytest.raises(RpcError):
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l1.rpc.withdraw(' 1nwldj5', 2 * amount)
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# overall max length exceeded
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with pytest.raises(RpcError):
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l1.rpc.withdraw('an84characterslonghumanreadablepartthatcontainsthenumber1andtheexcludedcharactersbio1569pvx', 2 * amount)
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# No separator character
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with pytest.raises(RpcError):
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l1.rpc.withdraw('pzry9x0s0muk', 2 * amount)
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# Empty HRP
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with pytest.raises(RpcError):
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l1.rpc.withdraw('1pzry9x0s0muk', 2 * amount)
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# Invalid witness version
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with pytest.raises(RpcError):
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l1.rpc.withdraw('BC13W508D6QEJXTDG4Y5R3ZARVARY0C5XW7KN40WF2', 2 * amount)
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# Invalid program length for witness version 0 (per BIP141)
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with pytest.raises(RpcError):
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l1.rpc.withdraw('BC1QR508D6QEJXTDG4Y5R3ZARVARYV98GJ9P', 2 * amount)
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# Mixed case
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with pytest.raises(RpcError):
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l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3q0sL5k7', 2 * amount)
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# Non-zero padding in 8-to-5 conversion
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with pytest.raises(RpcError):
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l1.rpc.withdraw('tb1qrp33g0q5c5txsp9arysrx4k6zdkfs4nce4xj0gdcccefvpysxf3pjxtptv', 2 * amount)
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# Should have 6 outputs available.
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assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 6
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# Test withdrawal to self.
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l1.rpc.withdraw(l1.rpc.newaddr('bech32')['bech32'], 'all', minconf=0)
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bitcoind.generate_block(1)
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assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 1
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l1.rpc.withdraw(waddr, 'all', minconf=0)
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assert l1.db_query('SELECT COUNT(*) as c FROM outputs WHERE status=0')[0]['c'] == 0
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# This should fail, can't even afford fee.
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with pytest.raises(RpcError, match=r'Cannot afford transaction'):
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l1.rpc.withdraw(waddr, 'all')
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# Add some funds to withdraw
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for i in range(10):
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l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01)
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bitcoind.generate_block(1)
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wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)
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# Try passing in a utxo set
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utxos = [utxo["txid"] + ":" + str(utxo["output"]) for utxo in l1.rpc.listfunds()["outputs"]][:4]
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withdrawal = l1.rpc.withdraw(waddr, 2 * amount, utxos=utxos)
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decode = bitcoind.rpc.decoderawtransaction(withdrawal['tx'])
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assert decode['txid'] == withdrawal['txid']
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# Check that correct utxos are included
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assert len(decode['vin']) == 4
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vins = ["{}:{}".format(v['txid'], v['vout']) for v in decode['vin']]
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for utxo in utxos:
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assert utxo in vins
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def test_minconf_withdraw(node_factory, bitcoind):
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"""Issue 2518: ensure that ridiculous confirmation levels don't overflow
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The number of confirmations is used to compute a maximum height that is to
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be accepted. If the current height is smaller than the number of
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confirmations we wrap around and just select everything. The fix is to
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clamp the maxheight parameter to a positive small number.
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"""
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amount = 1000000
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# Don't get any funds from previous runs.
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l1 = node_factory.get_node(random_hsm=True)
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addr = l1.rpc.newaddr()['bech32']
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# Add some funds to withdraw later
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for i in range(10):
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l1.bitcoin.rpc.sendtoaddress(addr, amount / 10**8 + 0.01)
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bitcoind.generate_block(1)
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wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)
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with pytest.raises(RpcError):
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l1.rpc.withdraw(destination=addr, satoshi=10000, feerate='normal', minconf=9999999)
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def test_addfunds_from_block(node_factory, bitcoind):
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"""Send funds to the daemon without telling it explicitly
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"""
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# Previous runs with same bitcoind can leave funds!
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l1 = node_factory.get_node(random_hsm=True)
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addr = l1.rpc.newaddr()['bech32']
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bitcoind.rpc.sendtoaddress(addr, 0.1)
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bitcoind.generate_block(1)
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wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 1)
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outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
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assert only_one(outputs)['value'] == 10000000
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# The address we detect must match what was paid to.
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output = only_one(l1.rpc.listfunds()['outputs'])
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assert output['address'] == addr
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# Send all our money to a P2WPKH address this time.
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addr = l1.rpc.newaddr("bech32")['bech32']
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l1.rpc.withdraw(addr, "all")
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bitcoind.generate_block(1)
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time.sleep(1)
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# The address we detect must match what was paid to.
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output = only_one(l1.rpc.listfunds()['outputs'])
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assert output['address'] == addr
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def test_txprepare(node_factory, bitcoind, chainparams):
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amount = 1000000
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l1 = node_factory.get_node(random_hsm=True)
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addr = chainparams['example_addr']
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# Add some funds to withdraw later: both bech32 and p2sh
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for i in range(5):
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bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'],
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amount / 10**8)
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bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'],
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amount / 10**8)
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bitcoind.generate_block(1)
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wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)
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prep = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 1000)}])
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decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx'])
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assert decode['txid'] == prep['txid']
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# 4 inputs, 2 outputs (3 if we have a fee output).
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assert len(decode['vin']) == 4
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assert len(decode['vout']) == 2 if not chainparams['feeoutput'] else 3
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# One output will be correct.
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outnum = [i for i, o in enumerate(decode['vout']) if o['value'] == Decimal(amount * 3) / 10**8][0]
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for i, o in enumerate(decode['vout']):
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if i == outnum:
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assert o['scriptPubKey']['type'] == 'witness_v0_keyhash'
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assert o['scriptPubKey']['addresses'] == [addr]
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else:
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assert o['scriptPubKey']['type'] in ['witness_v0_keyhash', 'fee']
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# Now prepare one with no change.
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prep2 = l1.rpc.txprepare([{addr: 'all'}])
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decode = bitcoind.rpc.decoderawtransaction(prep2['unsigned_tx'])
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assert decode['txid'] == prep2['txid']
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# 6 inputs, 1 outputs.
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assert len(decode['vin']) == 6
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assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2
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# Some fees will be paid.
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assert decode['vout'][0]['value'] < Decimal(amount * 6) / 10**8
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assert decode['vout'][0]['value'] > Decimal(amount * 6) / 10**8 - Decimal(0.0002)
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assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash'
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assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr]
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# If I cancel the first one, I can get those first 4 outputs.
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discard = l1.rpc.txdiscard(prep['txid'])
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assert discard['txid'] == prep['txid']
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assert discard['unsigned_tx'] == prep['unsigned_tx']
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prep3 = l1.rpc.txprepare([{addr: 'all'}])
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decode = bitcoind.rpc.decoderawtransaction(prep3['unsigned_tx'])
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assert decode['txid'] == prep3['txid']
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# 4 inputs, 1 outputs.
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assert len(decode['vin']) == 4
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assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2
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# Some fees will be taken
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assert decode['vout'][0]['value'] < Decimal(amount * 4) / 10**8
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assert decode['vout'][0]['value'] > Decimal(amount * 4) / 10**8 - Decimal(0.0002)
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assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash'
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assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr]
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# Cannot discard twice.
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with pytest.raises(RpcError, match=r'not an unreleased txid'):
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l1.rpc.txdiscard(prep['txid'])
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# Discard everything, we should now spend all inputs.
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l1.rpc.txdiscard(prep2['txid'])
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l1.rpc.txdiscard(prep3['txid'])
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prep4 = l1.rpc.txprepare([{addr: 'all'}])
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decode = bitcoind.rpc.decoderawtransaction(prep4['unsigned_tx'])
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assert decode['txid'] == prep4['txid']
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# 10 inputs, 1 outputs.
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assert len(decode['vin']) == 10
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assert len(decode['vout']) == 1 if not chainparams['feeoutput'] else 2
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# Some fees will be taken
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assert decode['vout'][0]['value'] < Decimal(amount * 10) / 10**8
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assert decode['vout'][0]['value'] > Decimal(amount * 10) / 10**8 - Decimal(0.0003)
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assert decode['vout'][0]['scriptPubKey']['type'] == 'witness_v0_keyhash'
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assert decode['vout'][0]['scriptPubKey']['addresses'] == [addr]
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l1.rpc.txdiscard(prep4['txid'])
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# Try passing in a utxo set
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utxos = [utxo["txid"] + ":" + str(utxo["output"]) for utxo in l1.rpc.listfunds()["outputs"]][:4]
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prep5 = l1.rpc.txprepare([{addr:
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Millisatoshi(amount * 3.5 * 1000)}], utxos=utxos)
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decode = bitcoind.rpc.decoderawtransaction(prep5['unsigned_tx'])
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assert decode['txid'] == prep5['txid']
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# Check that correct utxos are included
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assert len(decode['vin']) == 4
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vins = ["{}:{}".format(v['txid'], v['vout']) for v in decode['vin']]
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for utxo in utxos:
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assert utxo in vins
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# We should have a change output, so this is exact
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assert len(decode['vout']) == 3 if chainparams['feeoutput'] else 2
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assert decode['vout'][1]['value'] == Decimal(amount * 3.5) / 10**8
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assert decode['vout'][1]['scriptPubKey']['type'] == 'witness_v0_keyhash'
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assert decode['vout'][1]['scriptPubKey']['addresses'] == [addr]
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# Discard prep4 and get all funds again
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l1.rpc.txdiscard(prep5['txid'])
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with pytest.raises(RpcError, match=r'this destination wants all satoshi. The count of outputs can\'t be more than 1'):
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prep5 = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 1000)},
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{addr: 'all'}])
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prep5 = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 500 + 100000)},
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{addr: Millisatoshi(amount * 3 * 500 - 100000)}])
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decode = bitcoind.rpc.decoderawtransaction(prep5['unsigned_tx'])
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assert decode['txid'] == prep5['txid']
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# 4 inputs, 3 outputs(include change).
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assert len(decode['vin']) == 4
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assert len(decode['vout']) == 4 if chainparams['feeoutput'] else 3
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# One output will be correct.
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for i in range(3 + chainparams['feeoutput']):
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if decode['vout'][i - 1]['value'] == Decimal('0.01500100'):
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outnum1 = i - 1
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elif decode['vout'][i - 1]['value'] == Decimal('0.01499900'):
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outnum2 = i - 1
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else:
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changenum = i - 1
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assert decode['vout'][outnum1]['scriptPubKey']['type'] == 'witness_v0_keyhash'
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assert decode['vout'][outnum1]['scriptPubKey']['addresses'] == [addr]
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assert decode['vout'][outnum2]['scriptPubKey']['type'] == 'witness_v0_keyhash'
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assert decode['vout'][outnum2]['scriptPubKey']['addresses'] == [addr]
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assert decode['vout'][changenum]['scriptPubKey']['type'] == 'witness_v0_keyhash'
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def test_txsend(node_factory, bitcoind, chainparams):
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amount = 1000000
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l1 = node_factory.get_node(random_hsm=True)
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addr = chainparams['example_addr']
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# Add some funds to withdraw later: both bech32 and p2sh
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for i in range(5):
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bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'],
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amount / 10**8)
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bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'],
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amount / 10**8)
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bitcoind.generate_block(1)
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wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10)
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prep = l1.rpc.txprepare([{addr: Millisatoshi(amount * 3 * 1000)}])
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out = l1.rpc.txsend(prep['txid'])
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# Cannot discard after send!
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with pytest.raises(RpcError, match=r'not an unreleased txid'):
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l1.rpc.txdiscard(prep['txid'])
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wait_for(lambda: prep['txid'] in bitcoind.rpc.getrawmempool())
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# Signed tx should have same txid
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decode = bitcoind.rpc.decoderawtransaction(out['tx'])
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assert decode['txid'] == prep['txid']
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bitcoind.generate_block(1)
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# Change output should appear.
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if decode['vout'][0]['value'] == Decimal(amount * 3) / 10**8:
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changenum = 1
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elif decode['vout'][1]['value'] == Decimal(amount * 3) / 10**8:
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changenum = 0
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else:
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assert False
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# Those spent outputs are gone, but change output has arrived.
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wait_for(lambda: len(l1.rpc.listfunds()['outputs']) == 10 - len(decode['vin']) + 1)
|
|
|
|
# Change address should appear in listfunds()
|
|
assert decode['vout'][changenum]['scriptPubKey']['addresses'][0] in [f['address'] for f in l1.rpc.listfunds()['outputs']]
|
|
|
|
|
|
def test_txprepare_restart(node_factory, bitcoind, chainparams):
|
|
amount = 1000000
|
|
l1 = node_factory.get_node(may_fail=True)
|
|
addr = chainparams['example_addr']
|
|
|
|
# Add some funds to withdraw later: both bech32 and p2sh
|
|
for i in range(5):
|
|
bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'],
|
|
amount / 10**8)
|
|
bitcoind.rpc.sendtoaddress(l1.rpc.newaddr('p2sh-segwit')['p2sh-segwit'],
|
|
amount / 10**8)
|
|
bitcoind.generate_block(1)
|
|
wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10)
|
|
|
|
prep = l1.rpc.txprepare([{addr: 'all'}])
|
|
decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx'])
|
|
assert decode['txid'] == prep['txid']
|
|
# All 10 inputs
|
|
assert len(decode['vin']) == 10
|
|
|
|
# L1 will forget all about it.
|
|
l1.restart()
|
|
|
|
# It goes backwards in blockchain just in case there was a reorg. Wait.
|
|
wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10)
|
|
|
|
with pytest.raises(RpcError, match=r'not an unreleased txid'):
|
|
l1.rpc.txdiscard(prep['txid'])
|
|
|
|
prep = l1.rpc.txprepare([{addr: 'all'}])
|
|
|
|
decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx'])
|
|
assert decode['txid'] == prep['txid']
|
|
# All 10 inputs
|
|
assert len(decode['vin']) == 10
|
|
|
|
# This will also work if we simply kill it.
|
|
l1.restart(clean=False)
|
|
|
|
# It goes backwards in blockchain just in case there was a reorg. Wait.
|
|
wait_for(lambda: [o['status'] for o in l1.rpc.listfunds()['outputs']] == ['confirmed'] * 10)
|
|
|
|
# It should have logged this for each output.
|
|
for i in decode['vin']:
|
|
assert l1.daemon.is_in_log('wallet: reserved output {}/{} reset to available'.format(i['txid'], i['vout']))
|
|
|
|
prep = l1.rpc.txprepare([{addr: 'all'}])
|
|
decode = bitcoind.rpc.decoderawtransaction(prep['unsigned_tx'])
|
|
assert decode['txid'] == prep['txid']
|
|
# All 10 inputs
|
|
assert len(decode['vin']) == 10
|
|
|