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1581 lines
60 KiB
1581 lines
60 KiB
from collections import namedtuple
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from fixtures import * # noqa: F401,F403
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from lightning import RpcError
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from utils import DEVELOPER, only_one, wait_for, sync_blockheight, VALGRIND
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import os
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import pytest
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import time
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import random
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import shutil
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import unittest
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def test_connect(node_factory):
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l1, l2 = node_factory.line_graph(2, fundchannel=False)
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# These should be in openingd.
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assert l1.rpc.getpeer(l2.info['id'])['connected']
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assert l2.rpc.getpeer(l1.info['id'])['connected']
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assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0
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assert len(l2.rpc.getpeer(l1.info['id'])['channels']) == 0
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# Reconnect should be a noop
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ret = l1.rpc.connect(l2.info['id'], 'localhost', port=l2.port)
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assert ret['id'] == l2.info['id']
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ret = l2.rpc.connect(l1.info['id'], host='localhost', port=l1.port)
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assert ret['id'] == l1.info['id']
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# Should still only have one peer!
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assert len(l1.rpc.listpeers()) == 1
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assert len(l2.rpc.listpeers()) == 1
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# Should get reasonable error if unknown addr for peer.
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with pytest.raises(RpcError, match=r'No address known'):
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l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e')
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# Should get reasonable error if connection refuse.
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with pytest.raises(RpcError, match=r'Connection establishment: Connection refused'):
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l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', 1)
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# Should get reasonable error if wrong key for peer.
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with pytest.raises(RpcError, match=r'Cryptographic handshake: peer closed connection \(wrong key\?\)'):
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l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', l2.port)
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def test_connect_standard_addr(node_factory):
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"""Test standard node@host:port address
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"""
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l1, l2, l3 = node_factory.get_nodes(3)
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# node@host
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ret = l1.rpc.connect("{}@{}".format(l2.info['id'], 'localhost'), port=l2.port)
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assert ret['id'] == l2.info['id']
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# node@host:port
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ret = l1.rpc.connect("{}@localhost:{}".format(l3.info['id'], l3.port))
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assert ret['id'] == l3.info['id']
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# node@[ipv6]:port --- not supported by our CI
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# ret = l1.rpc.connect("{}@[::1]:{}".format(l3.info['id'], l3.port))
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# assert ret['id'] == l3.info['id']
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def test_reconnect_channel_peers(node_factory, executor):
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l1 = node_factory.get_node(may_reconnect=True)
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l2 = node_factory.get_node(may_reconnect=True)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.fund_channel(l2, 10**6)
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l2.restart()
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# Should reconnect.
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wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
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wait_for(lambda: only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected'])
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# Connect command should succeed.
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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# Stop l2 and wait for l1 to notice.
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l2.stop()
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wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
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# Now should fail.
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with pytest.raises(RpcError, match=r'Connection refused'):
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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# Wait for exponential backoff to give us a 2 second window.
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l1.daemon.wait_for_log('Will try reconnect in 2 seconds')
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# It should now succeed when it restarts.
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l2.start()
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# Multiples should be fine!
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fut1 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
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fut2 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
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fut3 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
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fut1.result(10)
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fut2.result(10)
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fut3.result(10)
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def test_balance(node_factory):
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l1, l2 = node_factory.line_graph(2, fundchannel=True)
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p1 = only_one(l1.rpc.getpeer(peer_id=l2.info['id'], level='info')['channels'])
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p2 = only_one(l2.rpc.getpeer(l1.info['id'], 'info')['channels'])
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assert p1['msatoshi_to_us'] == 10**6 * 1000
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assert p1['msatoshi_total'] == 10**6 * 1000
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assert p2['msatoshi_to_us'] == 0
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assert p2['msatoshi_total'] == 10**6 * 1000
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def test_bad_opening(node_factory):
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# l1 asks for a too-long locktime
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l1 = node_factory.get_node(options={'watchtime-blocks': 100})
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l2 = node_factory.get_node(options={'max-locktime-blocks': 99})
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ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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assert ret['id'] == l2.info['id']
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l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
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l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
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l1.fundwallet(10**6 + 1000000)
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with pytest.raises(RpcError):
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l1.rpc.fundchannel(l2.info['id'], 10**6)
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l2.daemon.wait_for_log('to_self_delay 100 larger than 99')
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def test_second_channel(node_factory):
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l1 = node_factory.get_node()
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l2 = node_factory.get_node()
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l3 = node_factory.get_node()
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
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l1.fund_channel(l2, 10**6)
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l1.fund_channel(l3, 10**6)
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_disconnect(node_factory):
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# These should all make us fail
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disconnects = ['-WIRE_INIT',
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'@WIRE_INIT',
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'+WIRE_INIT']
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l1 = node_factory.get_node(disconnect=disconnects)
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l2 = node_factory.get_node()
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with pytest.raises(RpcError):
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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with pytest.raises(RpcError):
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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with pytest.raises(RpcError):
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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# Should have 3 connect fails.
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for d in disconnects:
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l1.daemon.wait_for_log('Failed connected out for {}'
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.format(l2.info['id']))
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# Should still only have one peer!
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assert len(l1.rpc.listpeers()) == 1
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assert len(l2.rpc.listpeers()) == 1
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_disconnect_funder(node_factory):
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# Now error on funder side duringchannel open.
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disconnects = ['-WIRE_OPEN_CHANNEL',
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'@WIRE_OPEN_CHANNEL',
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'+WIRE_OPEN_CHANNEL',
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'-WIRE_FUNDING_CREATED',
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'@WIRE_FUNDING_CREATED']
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l1 = node_factory.get_node(disconnect=disconnects)
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l2 = node_factory.get_node()
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l1.fundwallet(2000000)
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for d in disconnects:
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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with pytest.raises(RpcError):
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l1.rpc.fundchannel(l2.info['id'], 20000)
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assert l1.rpc.getpeer(l2.info['id']) is None
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# This one will succeed.
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.rpc.fundchannel(l2.info['id'], 20000)
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# Should still only have one peer!
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assert len(l1.rpc.listpeers()) == 1
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assert len(l2.rpc.listpeers()) == 1
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_disconnect_fundee(node_factory):
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# Now error on fundee side during channel open.
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disconnects = ['-WIRE_ACCEPT_CHANNEL',
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'@WIRE_ACCEPT_CHANNEL',
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'+WIRE_ACCEPT_CHANNEL']
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l1 = node_factory.get_node()
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l2 = node_factory.get_node(disconnect=disconnects)
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l1.fundwallet(2000000)
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for d in disconnects:
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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with pytest.raises(RpcError):
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l1.rpc.fundchannel(l2.info['id'], 20000)
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assert l1.rpc.getpeer(l2.info['id']) is None
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# This one will succeed.
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.rpc.fundchannel(l2.info['id'], 20000)
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# Should still only have one peer!
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assert len(l1.rpc.listpeers()) == 1
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assert len(l2.rpc.listpeers()) == 1
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_disconnect_half_signed(node_factory):
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# Now, these are the corner cases. Fundee sends funding_signed,
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# but funder doesn't receive it.
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disconnects = ['@WIRE_FUNDING_SIGNED']
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l1 = node_factory.get_node()
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l2 = node_factory.get_node(disconnect=disconnects)
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l1.fundwallet(2000000)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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with pytest.raises(RpcError):
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l1.rpc.fundchannel(l2.info['id'], 20000)
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# Fundee remembers, funder doesn't.
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assert l1.rpc.getpeer(l2.info['id']) is None
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assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id']
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_reconnect_signed(node_factory):
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# This will fail *after* both sides consider channel opening.
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disconnects = ['+WIRE_FUNDING_SIGNED']
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l1 = node_factory.get_node(may_reconnect=True)
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l2 = node_factory.get_node(disconnect=disconnects,
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may_reconnect=True)
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l1.fundwallet(2000000)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.rpc.fundchannel(l2.info['id'], 20000)
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# They haven't forgotten each other.
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assert l1.rpc.getpeer(l2.info['id'])['id'] == l2.info['id']
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assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id']
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# Technically, this is async to fundchannel (and could reconnect first)
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l1.daemon.wait_for_logs(['sendrawtx exit 0',
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'Peer has reconnected, state CHANNELD_AWAITING_LOCKIN'])
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l1.bitcoin.generate_block(6)
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l1.daemon.wait_for_log(' to CHANNELD_NORMAL')
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l2.daemon.wait_for_log(' to CHANNELD_NORMAL')
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_reconnect_openingd(node_factory):
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# Openingd thinks we're still opening; funder reconnects..
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disconnects = ['0WIRE_ACCEPT_CHANNEL']
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l1 = node_factory.get_node(may_reconnect=True)
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l2 = node_factory.get_node(disconnect=disconnects,
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may_reconnect=True)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.fundwallet(2000000)
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# l2 closes on l1, l1 forgets.
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with pytest.raises(RpcError):
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l1.rpc.fundchannel(l2.info['id'], 20000)
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assert l1.rpc.getpeer(l2.info['id']) is None
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# Reconnect.
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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# We should get a message about reconnecting.
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l2.daemon.wait_for_log('Killing openingd: Reconnected')
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l2.daemon.wait_for_log('lightning_openingd.*Handed peer, entering loop')
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# Should work fine.
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l1.rpc.fundchannel(l2.info['id'], 20000)
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l1.daemon.wait_for_log('sendrawtx exit 0')
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# Just to be sure, second openingd hand over to channeld.
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l2.daemon.wait_for_log('lightning_openingd.*UPDATE WIRE_OPENING_FUNDEE')
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_reconnect_gossiping(node_factory):
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# connectd thinks we're still gossiping; peer reconnects.
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disconnects = ['0WIRE_PING']
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l1 = node_factory.get_node(may_reconnect=True)
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l2 = node_factory.get_node(disconnect=disconnects,
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may_reconnect=True)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l2.rpc.ping(l1.info['id'], 1, 65532)
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wait_for(lambda: l1.rpc.listpeers(l2.info['id'])['peers'] == [])
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l2.daemon.wait_for_log('processing now old peer gone')
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def test_connect_stresstest(node_factory, executor):
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# This test is unreliable, but it's better than nothing.
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l1 = node_factory.get_node(may_reconnect=True)
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l2 = node_factory.get_node(may_reconnect=True)
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l3 = node_factory.get_node(may_reconnect=True)
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# Hack l3 into a clone of l2, to stress reconnect code.
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l3.stop()
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shutil.copyfile(os.path.join(l2.daemon.lightning_dir, 'hsm_secret'),
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os.path.join(l3.daemon.lightning_dir, 'hsm_secret'))
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l3.start()
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l3.info = l3.rpc.getinfo()
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assert l3.info['id'] == l2.info['id']
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# We fire off random connect/disconnect commands.
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actions = [
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(l2.rpc.connect, l1.info['id'], 'localhost', l1.port),
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(l3.rpc.connect, l1.info['id'], 'localhost', l3.port),
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(l1.rpc.connect, l2.info['id'], 'localhost', l2.port),
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(l1.rpc.connect, l3.info['id'], 'localhost', l3.port),
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(l1.rpc.disconnect, l2.info['id'])
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]
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args = [random.choice(actions) for _ in range(1000)]
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# We get them all to connect to each other.
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futs = []
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for a in args:
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futs.append(executor.submit(*a))
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# We don't actually care if they fail, since some will.
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successes = 0
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failures = 0
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for f in futs:
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if f.exception():
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failures += 1
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else:
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f.result()
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successes += 1
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assert successes > failures
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_reconnect_normal(node_factory):
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# Should reconnect fine even if locked message gets lost.
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disconnects = ['-WIRE_FUNDING_LOCKED',
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'@WIRE_FUNDING_LOCKED',
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'+WIRE_FUNDING_LOCKED']
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l1 = node_factory.get_node(disconnect=disconnects,
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may_reconnect=True)
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l2 = node_factory.get_node(may_reconnect=True)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.fund_channel(l2, 10**6)
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_reconnect_sender_add1(node_factory):
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# Fail after add is OK, will cause payment failure though.
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disconnects = ['-WIRE_UPDATE_ADD_HTLC-nocommit',
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'+WIRE_UPDATE_ADD_HTLC-nocommit',
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'@WIRE_UPDATE_ADD_HTLC-nocommit']
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# Feerates identical so we don't get gratuitous commit to update them
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l1 = node_factory.get_node(disconnect=disconnects,
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may_reconnect=True,
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feerates=(7500, 7500, 7500))
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l2 = node_factory.get_node(may_reconnect=True)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.fund_channel(l2, 10**6)
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amt = 200000000
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rhash = l2.rpc.invoice(amt, 'test_reconnect_sender_add1', 'desc')['payment_hash']
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assert only_one(l2.rpc.listinvoices('test_reconnect_sender_add1')['invoices'])['status'] == 'unpaid'
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route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
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for i in range(0, len(disconnects)):
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l1.rpc.sendpay(route, rhash)
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with pytest.raises(RpcError):
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l1.rpc.waitsendpay(rhash)
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# Wait for reconnection.
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l1.daemon.wait_for_log('Already have funding locked in')
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# This will send commit, so will reconnect as required.
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l1.rpc.sendpay(route, rhash)
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@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
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def test_reconnect_sender_add(node_factory):
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disconnects = ['-WIRE_COMMITMENT_SIGNED',
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'@WIRE_COMMITMENT_SIGNED',
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'+WIRE_COMMITMENT_SIGNED',
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'-WIRE_REVOKE_AND_ACK',
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'@WIRE_REVOKE_AND_ACK',
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'+WIRE_REVOKE_AND_ACK']
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# Feerates identical so we don't get gratuitous commit to update them
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l1 = node_factory.get_node(disconnect=disconnects,
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may_reconnect=True,
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feerates=(7500, 7500, 7500))
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l2 = node_factory.get_node(may_reconnect=True)
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l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
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l1.fund_channel(l2, 10**6)
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amt = 200000000
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rhash = l2.rpc.invoice(amt, 'testpayment', 'desc')['payment_hash']
|
|
assert only_one(l2.rpc.listinvoices('testpayment')['invoices'])['status'] == 'unpaid'
|
|
|
|
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
|
|
|
|
# This will send commit, so will reconnect as required.
|
|
l1.rpc.sendpay(route, rhash)
|
|
# Should have printed this for every reconnect.
|
|
for i in range(0, len(disconnects)):
|
|
l1.daemon.wait_for_log('Already have funding locked in')
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
|
|
def test_reconnect_receiver_add(node_factory):
|
|
disconnects = ['-WIRE_COMMITMENT_SIGNED',
|
|
'@WIRE_COMMITMENT_SIGNED',
|
|
'+WIRE_COMMITMENT_SIGNED',
|
|
'-WIRE_REVOKE_AND_ACK',
|
|
'@WIRE_REVOKE_AND_ACK',
|
|
'+WIRE_REVOKE_AND_ACK']
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500))
|
|
l2 = node_factory.get_node(disconnect=disconnects,
|
|
may_reconnect=True)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
l1.fund_channel(l2, 10**6)
|
|
|
|
amt = 200000000
|
|
rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash']
|
|
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid'
|
|
|
|
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
|
|
l1.rpc.sendpay(route, rhash)
|
|
for i in range(len(disconnects)):
|
|
l1.daemon.wait_for_log('Already have funding locked in')
|
|
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid'
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
|
|
def test_reconnect_receiver_fulfill(node_factory):
|
|
# Ordering matters: after +WIRE_UPDATE_FULFILL_HTLC, channeld
|
|
# will continue and try to send WIRE_COMMITMENT_SIGNED: if
|
|
# that's the next failure, it will do two in one run.
|
|
disconnects = ['@WIRE_UPDATE_FULFILL_HTLC',
|
|
'+WIRE_UPDATE_FULFILL_HTLC',
|
|
'-WIRE_UPDATE_FULFILL_HTLC',
|
|
'-WIRE_COMMITMENT_SIGNED',
|
|
'@WIRE_COMMITMENT_SIGNED',
|
|
'+WIRE_COMMITMENT_SIGNED',
|
|
'-WIRE_REVOKE_AND_ACK',
|
|
'@WIRE_REVOKE_AND_ACK',
|
|
'+WIRE_REVOKE_AND_ACK']
|
|
l1 = node_factory.get_node(may_reconnect=True)
|
|
l2 = node_factory.get_node(disconnect=disconnects,
|
|
may_reconnect=True)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
l1.fund_channel(l2, 10**6)
|
|
|
|
amt = 200000000
|
|
rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash']
|
|
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid'
|
|
|
|
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
|
|
l1.rpc.sendpay(route, rhash)
|
|
for i in range(len(disconnects)):
|
|
l1.daemon.wait_for_log('Already have funding locked in')
|
|
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid'
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
|
|
def test_shutdown_reconnect(node_factory):
|
|
disconnects = ['-WIRE_SHUTDOWN',
|
|
'@WIRE_SHUTDOWN',
|
|
'+WIRE_SHUTDOWN']
|
|
l1 = node_factory.get_node(disconnect=disconnects,
|
|
may_reconnect=True)
|
|
l2 = node_factory.get_node(may_reconnect=True)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
chan = l1.fund_channel(l2, 10**6)
|
|
l1.pay(l2, 200000000)
|
|
|
|
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0
|
|
|
|
# This should return with an error, then close.
|
|
with pytest.raises(RpcError, match=r'Channel close negotiation not finished'):
|
|
l1.rpc.close(chan, False, 0)
|
|
|
|
l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
|
|
l2.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
|
|
|
|
l1.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
|
|
l2.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
|
|
|
|
# And should put closing into mempool (happens async, so
|
|
# CLOSINGD_COMPLETE may come first).
|
|
l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
|
|
l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
|
|
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1
|
|
|
|
|
|
def test_shutdown_awaiting_lockin(node_factory, bitcoind):
|
|
l1 = node_factory.get_node()
|
|
l2 = node_factory.get_node(options={'funding-confirms': 3})
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundwallet(10**6 + 1000000)
|
|
chanid = l1.rpc.fundchannel(l2.info['id'], 10**6)['channel_id']
|
|
|
|
# Technically, this is async to fundchannel.
|
|
l1.daemon.wait_for_log('sendrawtx exit 0')
|
|
bitcoind.generate_block(1)
|
|
|
|
# This should return with an error, then close.
|
|
with pytest.raises(RpcError, match=r'Channel close negotiation not finished'):
|
|
l1.rpc.close(chanid, False, 0)
|
|
|
|
l1.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN')
|
|
l2.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN')
|
|
|
|
l1.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE')
|
|
l2.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE')
|
|
|
|
# And should put closing into mempool (happens async, so
|
|
# CLOSINGD_COMPLETE may come first).
|
|
l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
|
|
l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
|
|
assert bitcoind.rpc.getmempoolinfo()['size'] == 1
|
|
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
bitcoind.generate_block(100)
|
|
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
|
|
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
|
|
|
|
|
|
def test_funding_change(node_factory, bitcoind):
|
|
"""Add some funds, fund a channel, and make sure we remember the change
|
|
"""
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=False)
|
|
l1.fundwallet(10000000)
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, [l1])
|
|
|
|
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
|
|
assert only_one(outputs)['value'] == 10000000
|
|
|
|
l1.rpc.fundchannel(l2.info['id'], 1000000)
|
|
outputs = {r['status']: r['value'] for r in l1.db_query(
|
|
'SELECT status, SUM(value) AS value FROM outputs GROUP BY status;')}
|
|
|
|
# The 10m out is spent and we have a change output of 9m-fee
|
|
assert outputs[0] > 8990000
|
|
assert outputs[2] == 10000000
|
|
|
|
|
|
def test_funding_all(node_factory, bitcoind):
|
|
"""Add some funds, fund a channel using all funds, make sure no funds remain
|
|
"""
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=False)
|
|
|
|
l1.fundwallet(0.1 * 10**8)
|
|
bitcoind.generate_block(1)
|
|
sync_blockheight(bitcoind, [l1])
|
|
|
|
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
|
|
assert only_one(outputs)['value'] == 10000000
|
|
|
|
l1.rpc.fundchannel(l2.info['id'], "all")
|
|
|
|
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
|
|
assert len(outputs) == 0
|
|
|
|
|
|
def test_funding_all_too_much(node_factory):
|
|
"""Add more than max possible funds, fund a channel using all funds we can.
|
|
"""
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=False)
|
|
|
|
l1.fundwallet(2**24 + 10000)
|
|
l1.rpc.fundchannel(l2.info['id'], "all")
|
|
|
|
assert only_one(l1.rpc.listfunds()['outputs'])['status'] == 'unconfirmed'
|
|
assert only_one(l1.rpc.listfunds()['channels'])['channel_total_sat'] == 2**24 - 1
|
|
|
|
|
|
def test_funding_fail(node_factory, bitcoind):
|
|
"""Add some funds, fund a channel without enough funds"""
|
|
# Previous runs with same bitcoind can leave funds!
|
|
max_locktime = 5 * 6 * 24
|
|
l1 = node_factory.get_node(random_hsm=True, options={'max-locktime-blocks': max_locktime})
|
|
l2 = node_factory.get_node(options={'watchtime-blocks': max_locktime + 1})
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
funds = 1000000
|
|
|
|
addr = l1.rpc.newaddr()['bech32']
|
|
l1.bitcoin.rpc.sendtoaddress(addr, funds / 10**8)
|
|
bitcoind.generate_block(1)
|
|
|
|
# Wait for it to arrive.
|
|
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0)
|
|
|
|
# Fail because l1 dislikes l2's huge locktime.
|
|
with pytest.raises(RpcError, match=r'to_self_delay \d+ larger than \d+'):
|
|
l1.rpc.fundchannel(l2.info['id'], int(funds / 10))
|
|
|
|
assert only_one(l1.rpc.listpeers()['peers'])['connected']
|
|
assert only_one(l2.rpc.listpeers()['peers'])['connected']
|
|
|
|
# Restart l2 without ridiculous locktime.
|
|
del l2.daemon.opts['watchtime-blocks']
|
|
l2.restart()
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
# We don't have enough left to cover fees if we try to spend it all.
|
|
with pytest.raises(RpcError, match=r'Cannot afford transaction'):
|
|
l1.rpc.fundchannel(l2.info['id'], funds)
|
|
|
|
# Should still be connected.
|
|
assert only_one(l1.rpc.listpeers()['peers'])['connected']
|
|
l2.daemon.wait_for_log('lightning_openingd-.*: Handed peer, entering loop')
|
|
assert only_one(l2.rpc.listpeers()['peers'])['connected']
|
|
|
|
# This works.
|
|
l1.rpc.fundchannel(l2.info['id'], int(funds / 10))
|
|
|
|
|
|
def test_funding_toolarge(node_factory, bitcoind):
|
|
"""Try to create a giant channel"""
|
|
l1 = node_factory.get_node()
|
|
l2 = node_factory.get_node()
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
# Send funds.
|
|
amount = 2**24
|
|
bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8 + 0.01)
|
|
bitcoind.generate_block(1)
|
|
|
|
# Wait for it to arrive.
|
|
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0)
|
|
|
|
# Fail to open (too large)
|
|
with pytest.raises(RpcError, match=r'Amount exceeded 16777215'):
|
|
l1.rpc.fundchannel(l2.info['id'], amount)
|
|
|
|
# This should work.
|
|
amount = amount - 1
|
|
l1.rpc.fundchannel(l2.info['id'], amount)
|
|
|
|
|
|
def test_lockin_between_restart(node_factory, bitcoind):
|
|
l1 = node_factory.get_node(may_reconnect=True)
|
|
l2 = node_factory.get_node(options={'funding-confirms': 3},
|
|
may_reconnect=True)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
l1.fundwallet(10**6 + 1000000)
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6)['tx']
|
|
|
|
# l1 goes down.
|
|
l1.stop()
|
|
|
|
# Now 120 blocks go by...
|
|
bitcoind.generate_block(120)
|
|
|
|
# Restart
|
|
l1.start()
|
|
|
|
# All should be good.
|
|
l1.daemon.wait_for_log(' to CHANNELD_NORMAL')
|
|
l2.daemon.wait_for_log(' to CHANNELD_NORMAL')
|
|
|
|
|
|
def test_funding_while_offline(node_factory, bitcoind):
|
|
l1 = node_factory.get_node()
|
|
addr = l1.rpc.newaddr()['bech32']
|
|
sync_blockheight(bitcoind, [l1])
|
|
|
|
# l1 goes down.
|
|
l1.stop()
|
|
|
|
# We send funds
|
|
bitcoind.rpc.sendtoaddress(addr, (10**6 + 1000000) / 10**8)
|
|
|
|
# Now 120 blocks go by...
|
|
bitcoind.generate_block(120)
|
|
|
|
# Restart
|
|
l1.start()
|
|
sync_blockheight(bitcoind, [l1])
|
|
|
|
assert len(l1.rpc.listfunds()['outputs']) == 1
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
|
|
def test_channel_persistence(node_factory, bitcoind, executor):
|
|
# Start two nodes and open a channel (to remember). l2 will
|
|
# mysteriously die while committing the first HTLC so we can
|
|
# check that HTLCs reloaded from the DB work.
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500))
|
|
l2 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'],
|
|
may_reconnect=True)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
# Neither node should have a channel open, they are just connected
|
|
for n in (l1, l2):
|
|
assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 0)
|
|
|
|
l1.fund_channel(l2, 100000)
|
|
|
|
peers = l1.rpc.listpeers()['peers']
|
|
assert(only_one(peers[0]['channels'])['state'] == 'CHANNELD_NORMAL')
|
|
|
|
# Both nodes should now have exactly one channel in the database
|
|
for n in (l1, l2):
|
|
assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 1)
|
|
|
|
# Fire off a sendpay request, it'll get interrupted by a restart
|
|
executor.submit(l1.pay, l2, 10000)
|
|
# Wait for it to be committed to, i.e., stored in the DB
|
|
l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
|
|
|
|
# Stop l2, l1 will reattempt to connect
|
|
print("Killing l2 in mid HTLC")
|
|
l2.daemon.kill()
|
|
|
|
# Clear the disconnect and timer stop so we can proceed normally
|
|
del l2.daemon.opts['dev-disconnect']
|
|
|
|
# Wait for l1 to notice
|
|
wait_for(lambda: 'connected' not in only_one(l1.rpc.listpeers()['peers'][0]['channels']))
|
|
|
|
# Now restart l2 and it should reload peers/channels from the DB
|
|
l2.start()
|
|
wait_for(lambda: len(l2.rpc.listpeers()['peers']) == 1)
|
|
|
|
# Wait for the restored HTLC to finish
|
|
wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99990000)
|
|
|
|
wait_for(lambda: len([p for p in l1.rpc.listpeers()['peers'] if p['connected']]))
|
|
wait_for(lambda: len([p for p in l2.rpc.listpeers()['peers'] if p['connected']]))
|
|
|
|
# Now make sure this is really functional by sending a payment
|
|
l1.pay(l2, 10000)
|
|
|
|
# L1 doesn't actually update msatoshi_to_us until it receives
|
|
# revoke_and_ack from L2, which can take a little bit.
|
|
wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000)
|
|
assert only_one(l2.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 20000
|
|
|
|
# Finally restart l1, and make sure it remembers
|
|
l1.restart()
|
|
assert only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000
|
|
|
|
# Now make sure l1 is watching for unilateral closes
|
|
l2.rpc.dev_fail(l1.info['id'])
|
|
l2.daemon.wait_for_log('Failing due to dev-fail command')
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
bitcoind.generate_block(1)
|
|
|
|
# L1 must notice.
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "gossip without DEVELOPER=1 is slow")
|
|
def test_private_channel(node_factory):
|
|
l1, l2 = node_factory.line_graph(2, announce_channels=False, wait_for_announce=False)
|
|
l3, l4 = node_factory.line_graph(2, announce_channels=True, wait_for_announce=True)
|
|
|
|
assert l1.daemon.is_in_log('Will open private channel with node {}'.format(l2.info['id']))
|
|
assert not l2.daemon.is_in_log('Will open private channel with node {}'.format(l1.info['id']))
|
|
assert not l3.daemon.is_in_log('Will open private channel with node {}'.format(l4.info['id']))
|
|
|
|
l3.daemon.wait_for_log('Received node_announcement for node {}'.format(l4.info['id']))
|
|
l4.daemon.wait_for_log('Received node_announcement for node {}'.format(l3.info['id']))
|
|
|
|
assert not l1.daemon.is_in_log('Received node_announcement for node {}'.format(l2.info['id']))
|
|
assert not l2.daemon.is_in_log('Received node_announcement for node {}'.format(l1.info['id']))
|
|
|
|
# test for 'private' flag in rpc output
|
|
assert only_one(only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['channels'])['private']
|
|
# check non-private channel
|
|
assert not only_one(only_one(l4.rpc.listpeers(l3.info['id'])['peers'])['channels'])['private']
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval")
|
|
def test_channel_reenable(node_factory):
|
|
l1, l2 = node_factory.line_graph(2, opts={'may_reconnect': True}, fundchannel=True, wait_for_announce=True)
|
|
|
|
l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id']))
|
|
l2.daemon.wait_for_log('Received node_announcement for node {}'.format(l1.info['id']))
|
|
|
|
# Both directions should be active before the restart
|
|
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True])
|
|
|
|
# Restart l2, will cause l1 to reconnect
|
|
l2.stop()
|
|
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [False, False])
|
|
l2.start()
|
|
|
|
# Updates may be suppressed if redundant; just test results.
|
|
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True])
|
|
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels()['channels']] == [True, True])
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
|
|
def test_update_fee(node_factory, bitcoind):
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=True)
|
|
chanid = l1.get_channel_scid(l2)
|
|
|
|
# Make l1 send out feechange.
|
|
l1.set_feerates((14000, 7500, 3750))
|
|
l2.daemon.wait_for_log('peer updated fee to 14000')
|
|
|
|
# Now make sure an HTLC works.
|
|
# (First wait for route propagation.)
|
|
l1.wait_channel_active(chanid)
|
|
sync_blockheight(bitcoind, [l1, l2])
|
|
|
|
# Make payments.
|
|
l1.pay(l2, 200000000)
|
|
l2.pay(l1, 100000000)
|
|
|
|
# Now shutdown cleanly.
|
|
with pytest.raises(RpcError, match=r'Channel close negotiation not finished'):
|
|
l1.rpc.close(chanid, False, 0)
|
|
|
|
l1.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
|
|
l2.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
|
|
|
|
# And should put closing into mempool.
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
bitcoind.generate_block(99)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
|
|
def test_fee_limits(node_factory):
|
|
# FIXME: Test case where opening denied.
|
|
l1, l2 = node_factory.line_graph(2, opts={'dev-max-fee-multiplier': 5, 'may_reconnect': True}, fundchannel=True)
|
|
|
|
# L1 asks for stupid low fee (will actually hit the floor of 253)
|
|
l1.stop()
|
|
l1.set_feerates((15, 15, 15), False)
|
|
l1.start()
|
|
|
|
l1.daemon.wait_for_log('Peer permanent failure in CHANNELD_NORMAL: lightning_channeld: received ERROR channel .*: update_fee 253 outside range 1875-75000')
|
|
# Make sure the resolution of this one doesn't interfere with the next!
|
|
# Note: may succeed, may fail with insufficient fee, depending on how
|
|
# bitcoind feels!
|
|
l1.daemon.wait_for_log('sendrawtx exit')
|
|
|
|
# Restore to normal.
|
|
l1.stop()
|
|
l1.set_feerates((15000, 7500, 3750), False)
|
|
l1.start()
|
|
|
|
# Try with node which sets --ignore-fee-limits
|
|
l3 = node_factory.get_node(options={'ignore-fee-limits': 'true'}, may_reconnect=True)
|
|
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
chan = l1.fund_channel(l3, 10**6)
|
|
|
|
# Try stupid high fees
|
|
l1.stop()
|
|
l1.set_feerates((15000 * 10, 7500, 3750), False)
|
|
l1.start()
|
|
|
|
l3.daemon.wait_for_log('peer_in WIRE_UPDATE_FEE')
|
|
l3.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
|
|
|
|
# We need to wait until both have committed and revoked the
|
|
# old state, otherwise we'll still try to commit with the old
|
|
# 15sat/byte fee
|
|
l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
|
|
|
|
# This should wait for close to complete
|
|
l1.rpc.close(chan)
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
|
|
def test_update_fee_reconnect(node_factory, bitcoind):
|
|
# Disconnect after first commitsig.
|
|
disconnects = ['+WIRE_COMMITMENT_SIGNED']
|
|
# Feerates identical so we don't get gratuitous commit to update them
|
|
l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True,
|
|
feerates=(15000, 15000, 3750))
|
|
# We match l2's later feerate, so we agree on same closing tx for simplicity.
|
|
l2 = node_factory.get_node(may_reconnect=True,
|
|
feerates=(14000, 14000, 3750))
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
chan = l1.fund_channel(l2, 10**6)
|
|
|
|
# Make l1 send out feechange; triggers disconnect/reconnect.
|
|
# (Note: < 10% change, so no smoothing here!)
|
|
l1.set_feerates((14000, 14000, 3750))
|
|
l1.daemon.wait_for_log('Setting REMOTE feerate to 14000')
|
|
l2.daemon.wait_for_log('Setting LOCAL feerate to 14000')
|
|
l1.daemon.wait_for_log(r'dev_disconnect: \+WIRE_COMMITMENT_SIGNED')
|
|
|
|
# Wait for reconnect....
|
|
l1.daemon.wait_for_log('Applying feerate 14000 to LOCAL')
|
|
|
|
l1.pay(l2, 200000000)
|
|
l2.pay(l1, 100000000)
|
|
|
|
# They should both have gotten commits with correct feerate.
|
|
assert l1.daemon.is_in_log('got commitsig [0-9]*: feerate 14000')
|
|
assert l2.daemon.is_in_log('got commitsig [0-9]*: feerate 14000')
|
|
|
|
# Now shutdown cleanly.
|
|
l1.rpc.close(chan)
|
|
|
|
# And should put closing into mempool.
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
l2.wait_for_channel_onchain(l1.info['id'])
|
|
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log(' to ONCHAIN')
|
|
l2.daemon.wait_for_log(' to ONCHAIN')
|
|
|
|
bitcoind.generate_block(99)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "Too slow without --dev-bitcoind-poll")
|
|
def test_multiple_channels(node_factory):
|
|
l1 = node_factory.get_node()
|
|
l2 = node_factory.get_node()
|
|
|
|
for i in range(3):
|
|
# FIXME: we shouldn't disconnect on close?
|
|
ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
assert ret['id'] == l2.info['id']
|
|
|
|
l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
|
|
l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
|
|
chan = l1.fund_channel(l2, 10**6)
|
|
|
|
l1.rpc.close(chan)
|
|
|
|
channels = only_one(l1.rpc.listpeers()['peers'])['channels']
|
|
assert len(channels) == 3
|
|
# Most in state ONCHAIN, last is CLOSINGD_COMPLETE
|
|
for i in range(len(channels) - 1):
|
|
assert channels[i]['state'] == 'ONCHAIN'
|
|
assert channels[-1]['state'] == 'CLOSINGD_COMPLETE'
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
|
|
def test_forget_channel(node_factory):
|
|
l1 = node_factory.get_node()
|
|
l2 = node_factory.get_node()
|
|
l1.fundwallet(10**6)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.rpc.fundchannel(l2.info['id'], 10**5)
|
|
|
|
assert len(l1.rpc.listpeers()['peers']) == 1
|
|
|
|
# This should fail, the funding tx is in the mempool and may confirm
|
|
with pytest.raises(RpcError, match=r'Cowardly refusing to forget channel'):
|
|
l1.rpc.dev_forget_channel(l2.info['id'])
|
|
|
|
assert len(l1.rpc.listpeers()['peers']) == 1
|
|
|
|
# Forcing should work
|
|
l1.rpc.dev_forget_channel(l2.info['id'], True)
|
|
assert len(l1.rpc.listpeers()['peers']) == 0
|
|
|
|
# And restarting should keep that peer forgotten
|
|
l1.restart()
|
|
assert len(l1.rpc.listpeers()['peers']) == 0
|
|
|
|
|
|
def test_peerinfo(node_factory, bitcoind):
|
|
l1, l2 = node_factory.line_graph(2, fundchannel=False, opts={'may_reconnect': True})
|
|
lfeatures = '8a'
|
|
# Gossiping but no node announcement yet
|
|
assert l1.rpc.getpeer(l2.info['id'])['connected']
|
|
assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0
|
|
assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures
|
|
|
|
# Fund a channel to force a node announcement
|
|
chan = l1.fund_channel(l2, 10**6)
|
|
# Now proceed to funding-depth and do a full gossip round
|
|
bitcoind.generate_block(5)
|
|
l1.daemon.wait_for_logs(['Received node_announcement for node ' + l2.info['id']])
|
|
l2.daemon.wait_for_logs(['Received node_announcement for node ' + l1.info['id']])
|
|
|
|
# Should have announced the same global features as told to peer.
|
|
nodes1 = l1.rpc.listnodes(l2.info['id'])['nodes']
|
|
nodes2 = l2.rpc.listnodes(l2.info['id'])['nodes']
|
|
peer1 = l1.rpc.getpeer(l2.info['id'])
|
|
peer2 = l2.rpc.getpeer(l1.info['id'])
|
|
assert only_one(nodes1)['globalfeatures'] == peer1['globalfeatures']
|
|
assert only_one(nodes2)['globalfeatures'] == peer2['globalfeatures']
|
|
|
|
assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures
|
|
assert l2.rpc.getpeer(l1.info['id'])['localfeatures'] == lfeatures
|
|
|
|
# If it reconnects after db load, it should know features.
|
|
l1.restart()
|
|
wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected'])
|
|
wait_for(lambda: l2.rpc.getpeer(l1.info['id'])['connected'])
|
|
assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures
|
|
assert l2.rpc.getpeer(l1.info['id'])['localfeatures'] == lfeatures
|
|
|
|
# Close the channel to forget the peer
|
|
with pytest.raises(RpcError, match=r'Channel close negotiation not finished'):
|
|
l1.rpc.close(chan, False, 0)
|
|
|
|
wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
|
|
wait_for(lambda: not only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected'])
|
|
|
|
bitcoind.generate_block(100)
|
|
l1.daemon.wait_for_log('WIRE_ONCHAIN_ALL_IRREVOCABLY_RESOLVED')
|
|
l2.daemon.wait_for_log('WIRE_ONCHAIN_ALL_IRREVOCABLY_RESOLVED')
|
|
|
|
# The only channel was closed, everybody should have forgotten the nodes
|
|
assert l1.rpc.listnodes()['nodes'] == []
|
|
assert l2.rpc.listnodes()['nodes'] == []
|
|
|
|
|
|
def test_disconnectpeer(node_factory, bitcoind):
|
|
l1, l2, l3 = node_factory.get_nodes(3, opts={'may_reconnect': False})
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
|
|
# Gossiping
|
|
assert l1.rpc.getpeer(l2.info['id'])['connected']
|
|
assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0
|
|
assert l1.rpc.getpeer(l3.info['id'])['connected']
|
|
assert len(l1.rpc.getpeer(l3.info['id'])['channels']) == 0
|
|
wait_for(lambda: l2.rpc.getpeer(l1.info['id']) is not None)
|
|
|
|
# Disconnect l2 from l1
|
|
l1.rpc.disconnect(l2.info['id'])
|
|
|
|
# Make sure listpeers no longer returns the disconnected node
|
|
assert l1.rpc.getpeer(l2.info['id']) is None
|
|
wait_for(lambda: l2.rpc.getpeer(l1.info['id']) is None)
|
|
|
|
# Make sure you cannot disconnect after disconnecting
|
|
with pytest.raises(RpcError, match=r'Peer not connected'):
|
|
l1.rpc.disconnect(l2.info['id'])
|
|
with pytest.raises(RpcError, match=r'Peer not connected'):
|
|
l2.rpc.disconnect(l1.info['id'])
|
|
|
|
# Fund channel l1 -> l3
|
|
l1.fund_channel(l3, 10**6)
|
|
bitcoind.generate_block(5)
|
|
|
|
# disconnecting a non gossiping peer results in error
|
|
with pytest.raises(RpcError, match=r'Peer is in state CHANNELD_NORMAL'):
|
|
l1.rpc.disconnect(l3.info['id'])
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs --dev-max-funding-unconfirmed-blocks")
|
|
def test_fundee_forget_funding_tx_unconfirmed(node_factory, bitcoind):
|
|
"""Test that fundee will forget the channel if
|
|
the funding tx has been unconfirmed for too long.
|
|
"""
|
|
# Keep this low (default is 2016), since everything
|
|
# is much slower in VALGRIND mode and wait_for_log
|
|
# could time out before lightningd processes all the
|
|
# blocks.
|
|
blocks = 200
|
|
# funder
|
|
l1 = node_factory.get_node()
|
|
# fundee
|
|
l2 = node_factory.get_node(options={"dev-max-funding-unconfirmed-blocks": blocks})
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
# Give funder some funds.
|
|
l1.fundwallet(10**7)
|
|
# Let blocks settle.
|
|
time.sleep(1)
|
|
|
|
def mock_sendrawtransaction(r):
|
|
return {'id': r['id'], 'error': {'code': 100, 'message': 'sendrawtransaction disabled'}}
|
|
|
|
# Prevent funder from broadcasting funding tx (any tx really).
|
|
l1.daemon.rpcproxy.mock_rpc('sendrawtransaction', mock_sendrawtransaction)
|
|
|
|
# Fund the channel.
|
|
# The process will complete, but funder will be unable
|
|
# to broadcast and confirm funding tx.
|
|
with pytest.raises(RpcError, match=r'sendrawtransaction disabled'):
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6)
|
|
|
|
# Generate blocks until unconfirmed.
|
|
bitcoind.generate_block(blocks)
|
|
|
|
# fundee will forget channel!
|
|
l2.daemon.wait_for_log('Forgetting channel: It has been {} blocks'.format(blocks))
|
|
|
|
# fundee will also forget and disconnect from peer.
|
|
assert len(l2.rpc.listpeers(l1.info['id'])['peers']) == 0
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs dev_fail")
|
|
def test_no_fee_estimate(node_factory, bitcoind, executor):
|
|
l1 = node_factory.get_node(start=False)
|
|
|
|
# Fail any fee estimation requests until we allow them further down
|
|
l1.daemon.rpcproxy.mock_rpc('estimatesmartfee', {
|
|
'error': {"errors": ["Insufficient data or no feerate found"], "blocks": 0}
|
|
})
|
|
l1.start()
|
|
|
|
l2 = node_factory.get_node()
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
|
|
# Can't fund a channel.
|
|
l1.fundwallet(10**7)
|
|
with pytest.raises(RpcError, match=r'Cannot estimate fees'):
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6)
|
|
|
|
# Can't withdraw either.
|
|
with pytest.raises(RpcError, match=r'Cannot estimate fees'):
|
|
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all')
|
|
|
|
# Can't use feerate names, either.
|
|
with pytest.raises(RpcError, match=r'Cannot estimate fees'):
|
|
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'urgent')
|
|
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'normal')
|
|
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'slow')
|
|
|
|
with pytest.raises(RpcError, match=r'Cannot estimate fees'):
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6, 'urgent')
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6, 'normal')
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6, 'slow')
|
|
|
|
# Can with manual feerate.
|
|
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 10000, '1500perkb')
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6, '2000perkw', minconf=0)
|
|
|
|
# Make sure we clean up cahnnel for later attempt.
|
|
l1.daemon.wait_for_log('sendrawtx exit 0')
|
|
l1.rpc.dev_fail(l2.info['id'])
|
|
l1.daemon.wait_for_log('Failing due to dev-fail command')
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
bitcoind.generate_block(6)
|
|
wait_for(lambda: only_one(l1.rpc.getpeer(l2.info['id'])['channels'])['state'] == 'ONCHAIN')
|
|
wait_for(lambda: only_one(l2.rpc.getpeer(l1.info['id'])['channels'])['state'] == 'ONCHAIN')
|
|
|
|
# But can accept incoming connections.
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l2.fund_channel(l1, 10**6)
|
|
|
|
# Can do HTLCs.
|
|
l2.pay(l1, 10**5)
|
|
|
|
# Can do mutual close.
|
|
l1.rpc.close(l2.info['id'])
|
|
bitcoind.generate_block(100)
|
|
|
|
# Can do unilateral close.
|
|
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
l2.fund_channel(l1, 10**6)
|
|
l2.pay(l1, 10**9 // 2)
|
|
l1.rpc.dev_fail(l2.info['id'])
|
|
l1.daemon.wait_for_log('Failing due to dev-fail command')
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
bitcoind.generate_block(5)
|
|
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) > 0)
|
|
bitcoind.generate_block(100)
|
|
|
|
# Start estimatesmartfee.
|
|
l1.set_feerates((15000, 7500, 3750), True)
|
|
|
|
# Can now fund a channel (as a test, use slow feerate).
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.rpc.fundchannel(l2.info['id'], 10**6, 'slow')
|
|
|
|
# Can withdraw (use urgent feerate).
|
|
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'urgent')
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs --dev-disconnect")
|
|
def test_funder_feerate_reconnect(node_factory, bitcoind):
|
|
# l1 updates fees, then reconnect so l2 retransmits commitment_signed.
|
|
disconnects = ['-WIRE_COMMITMENT_SIGNED']
|
|
l1 = node_factory.get_node(may_reconnect=True,
|
|
feerates=(7500, 7500, 7500))
|
|
l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fund_channel(l2, 10**6)
|
|
|
|
# create fee update, causing disconnect.
|
|
l1.set_feerates((15000, 7500, 3750))
|
|
l2.daemon.wait_for_log(r'dev_disconnect: \-WIRE_COMMITMENT_SIGNED')
|
|
|
|
# Wait until they reconnect.
|
|
l1.daemon.wait_for_log('Peer transient failure in CHANNELD_NORMAL')
|
|
wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected'])
|
|
|
|
# Should work normally.
|
|
l1.pay(l2, 200000000)
|
|
|
|
|
|
def test_funder_simple_reconnect(node_factory, bitcoind):
|
|
"""Sanity check that reconnection works with completely unused channels"""
|
|
# Set fees even so it doesn't send any commitments.
|
|
l1 = node_factory.get_node(may_reconnect=True,
|
|
feerates=(7500, 7500, 7500))
|
|
l2 = node_factory.get_node(may_reconnect=True)
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fund_channel(l2, 10**6)
|
|
|
|
l1.rpc.disconnect(l2.info['id'], True)
|
|
|
|
# Wait until they reconnect.
|
|
wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected'])
|
|
|
|
# Should work normally.
|
|
l1.pay(l2, 200000000)
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs LIGHTNINGD_DEV_LOG_IO")
|
|
def test_dataloss_protection(node_factory, bitcoind):
|
|
l1 = node_factory.get_node(may_reconnect=True, log_all_io=True,
|
|
feerates=(7500, 7500, 7500))
|
|
l2 = node_factory.get_node(may_reconnect=True, log_all_io=True,
|
|
feerates=(7500, 7500, 7500))
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
# l1 should send out WIRE_INIT (0010)
|
|
l1.daemon.wait_for_log(r"\[OUT\] 0010"
|
|
# gflen == 0
|
|
"0000"
|
|
# lflen == 1
|
|
"0001"
|
|
# Local features 1, 3 and 7 (0x8a).
|
|
"8a")
|
|
|
|
l1.fund_channel(l2, 10**6)
|
|
l2.stop()
|
|
|
|
# Save copy of the db.
|
|
dbpath = os.path.join(l2.daemon.lightning_dir, "lightningd.sqlite3")
|
|
orig_db = open(dbpath, "rb").read()
|
|
l2.start()
|
|
|
|
# l1 should have sent WIRE_CHANNEL_REESTABLISH with option_data_loss_protect.
|
|
l1.daemon.wait_for_log(r"\[OUT\] 0088"
|
|
# channel_id
|
|
"[0-9a-f]{64}"
|
|
# next_local_commitment_number
|
|
"0000000000000001"
|
|
# next_remote_revocation_number
|
|
"0000000000000000"
|
|
# your_last_per_commitment_secret (funding_depth may
|
|
# trigger a fee-update and commit, hence this may not
|
|
# be zero)
|
|
"[0-9a-f]{64}"
|
|
# my_current_per_commitment_point
|
|
"0[23][0-9a-f]{64}")
|
|
# After an htlc, we should get different results (two more commits)
|
|
l1.pay(l2, 200000000)
|
|
|
|
# Make sure both sides consider it completely settled (has received both
|
|
# REVOKE_AND_ACK)
|
|
l1.daemon.wait_for_logs([r"\[IN\] 0085"] * 2)
|
|
l2.daemon.wait_for_logs([r"\[IN\] 0085"] * 2)
|
|
|
|
l2.restart()
|
|
|
|
# l1 should have sent WIRE_CHANNEL_REESTABLISH with option_data_loss_protect.
|
|
l1.daemon.wait_for_log(r"\[OUT\] 0088"
|
|
# channel_id
|
|
"[0-9a-f]{64}"
|
|
# next_local_commitment_number
|
|
"000000000000000[1-9]"
|
|
# next_remote_revocation_number
|
|
"000000000000000[1-9]"
|
|
# your_last_per_commitment_secret
|
|
"[0-9a-f]{64}"
|
|
# my_current_per_commitment_point
|
|
"0[23][0-9a-f]{64}")
|
|
|
|
# Now, move l2 back in time.
|
|
l2.stop()
|
|
# Overwrite with OLD db.
|
|
open(dbpath, "wb").write(orig_db)
|
|
l2.start()
|
|
|
|
# l2 should freak out!
|
|
l2.daemon.wait_for_log("Peer permanent failure in CHANNELD_NORMAL: Awaiting unilateral close")
|
|
|
|
# l1 should drop to chain.
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
|
|
# l2 must NOT drop to chain.
|
|
l2.daemon.wait_for_log("Cannot broadcast our commitment tx: they have a future one")
|
|
assert not l2.daemon.is_in_log('sendrawtx exit 0')
|
|
|
|
closetxid = only_one(bitcoind.rpc.getrawmempool(False))
|
|
|
|
# l2 should still recover something!
|
|
bitcoind.generate_block(1)
|
|
|
|
l2.daemon.wait_for_log("ERROR: Unknown commitment #[0-9], recovering our funds!")
|
|
|
|
# Restarting l2, and it should remember from db.
|
|
l2.restart()
|
|
|
|
l2.daemon.wait_for_log("ERROR: Unknown commitment #[0-9], recovering our funds!")
|
|
bitcoind.generate_block(100)
|
|
l2.daemon.wait_for_log('WIRE_ONCHAIN_ALL_IRREVOCABLY_RESOLVED')
|
|
|
|
# l2 should have it in wallet.
|
|
assert (closetxid, "confirmed") in set([(o['txid'], o['status']) for o in l2.rpc.listfunds()['outputs']])
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs dev_disconnect")
|
|
def test_restart_multi_htlc_rexmit(node_factory, bitcoind, executor):
|
|
# l1 disables commit timer once we send first htlc, dies on commit
|
|
disconnects = ['=WIRE_UPDATE_ADD_HTLC-nocommit',
|
|
'-WIRE_COMMITMENT_SIGNED']
|
|
l1, l2 = node_factory.line_graph(2, opts=[{'disconnect': disconnects,
|
|
'may_reconnect': True},
|
|
{'may_reconnect': True}])
|
|
|
|
executor.submit(l1.pay, l2, 20000)
|
|
executor.submit(l1.pay, l2, 30000)
|
|
|
|
l1.daemon.wait_for_logs(['peer_out WIRE_UPDATE_ADD_HTLC'] * 2)
|
|
l1.rpc.dev_reenable_commit(l2.info['id'])
|
|
l1.daemon.wait_for_log('dev_disconnect: -WIRE_COMMITMENT_SIGNED')
|
|
|
|
# This will make it reconnect
|
|
l1.stop()
|
|
# Clear the disconnect so we can proceed normally
|
|
del l1.daemon.opts['dev-disconnect']
|
|
l1.start()
|
|
|
|
# Payments will fail due to restart, but we can see results in listsendpays.
|
|
print(l1.rpc.listsendpays())
|
|
wait_for(lambda: [p['status'] for p in l1.rpc.listsendpays()['payments']] == ['complete', 'complete'])
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "needs dev-disconnect")
|
|
def test_fulfill_incoming_first(node_factory, bitcoind):
|
|
"""Test that we handle the case where we completely resolve incoming htlc
|
|
before fulfilled outgoing htlc"""
|
|
|
|
# We agree on fee change first, then add HTLC, then remove; stop after remove.
|
|
disconnects = ['+WIRE_COMMITMENT_SIGNED*3']
|
|
# We manually reconnect l2 & l3, after 100 blocks; hence allowing manual
|
|
# reconnect, but disabling auto connect, and massive cltv so 2/3 doesn't
|
|
# time out.
|
|
l1, l2, l3 = node_factory.line_graph(3, opts=[{},
|
|
{'may_reconnect': True,
|
|
'dev-no-reconnect': None},
|
|
{'may_reconnect': True,
|
|
'dev-no-reconnect': None,
|
|
'disconnect': disconnects,
|
|
'cltv-final': 200}],
|
|
wait_for_announce=True)
|
|
|
|
# This succeeds.
|
|
l1.rpc.pay(l3.rpc.invoice(200000000, 'test_fulfill_incoming_first', 'desc')['bolt11'])
|
|
|
|
# l1 can shutdown, fine.
|
|
l1.rpc.close(l2.info['id'])
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
bitcoind.generate_block(100)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# Now, l2 should restore from DB fine, even though outgoing HTLC no longer
|
|
# has an incoming.
|
|
l2.restart()
|
|
|
|
# Manually reconnect l2->l3.
|
|
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
|
|
|
|
# Fulfill should be retransmitted OK (ignored result).
|
|
l2.rpc.close(l3.info['id'])
|
|
l2.wait_for_channel_onchain(l3.info['id'])
|
|
bitcoind.generate_block(100)
|
|
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
l3.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "gossip without DEVELOPER=1 is slow")
|
|
def test_restart_many_payments(node_factory):
|
|
l1 = node_factory.get_node(may_reconnect=True)
|
|
|
|
# On my laptop, these take 74 seconds and 44 seconds (with restart commented out)
|
|
if VALGRIND:
|
|
num = 2
|
|
else:
|
|
num = 5
|
|
|
|
# Nodes with channels into the main node
|
|
innodes = node_factory.get_nodes(num, opts={'may_reconnect': True})
|
|
inchans = []
|
|
for n in innodes:
|
|
n.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
inchans.append(n.fund_channel(l1, 10**6, False))
|
|
|
|
# Nodes with channels out of the main node
|
|
outnodes = node_factory.get_nodes(len(innodes), opts={'may_reconnect': True})
|
|
outchans = []
|
|
for n in outnodes:
|
|
n.rpc.connect(l1.info['id'], 'localhost', l1.port)
|
|
outchans.append(l1.fund_channel(n, 10**6, False))
|
|
|
|
# Now do all the waiting at once: if !DEVELOPER, this can be *very* slow!
|
|
l1_logs = []
|
|
for i in range(len(innodes)):
|
|
scid = inchans[i]
|
|
l1_logs += [r'update for channel {}/0 now ACTIVE'.format(scid),
|
|
r'update for channel {}/1 now ACTIVE'.format(scid),
|
|
'to CHANNELD_NORMAL']
|
|
innodes[i].daemon.wait_for_logs([r'update for channel {}/0 now ACTIVE'
|
|
.format(scid),
|
|
r'update for channel {}/1 now ACTIVE'
|
|
.format(scid),
|
|
'to CHANNELD_NORMAL'])
|
|
|
|
for i in range(len(outnodes)):
|
|
scid = outchans[i]
|
|
l1_logs += [r'update for channel {}/0 now ACTIVE'.format(scid),
|
|
r'update for channel {}/1 now ACTIVE'.format(scid),
|
|
'to CHANNELD_NORMAL']
|
|
outnodes[i].daemon.wait_for_logs([r'update for channel {}/0 now ACTIVE'
|
|
.format(scid),
|
|
r'update for channel {}/1 now ACTIVE'
|
|
.format(scid),
|
|
'to CHANNELD_NORMAL'])
|
|
|
|
l1.daemon.wait_for_logs(l1_logs)
|
|
|
|
# Manually create routes, get invoices
|
|
Payment = namedtuple('Payment', ['innode', 'route', 'payment_hash'])
|
|
|
|
to_pay = []
|
|
for i in range(len(innodes)):
|
|
# This one will cause WIRE_INCORRECT_CLTV_EXPIRY from l1.
|
|
route = [{'msatoshi': 100001001,
|
|
'id': l1.info['id'],
|
|
'delay': 10,
|
|
'channel': inchans[i]},
|
|
{'msatoshi': 100000000,
|
|
'id': outnodes[i].info['id'],
|
|
'delay': 5,
|
|
'channel': outchans[i]}]
|
|
payment_hash = outnodes[i].rpc.invoice(100000000, "invoice", "invoice")['payment_hash']
|
|
to_pay.append(Payment(innodes[i], route, payment_hash))
|
|
|
|
# This one should be routed through to the outnode.
|
|
route = [{'msatoshi': 100001001,
|
|
'id': l1.info['id'],
|
|
'delay': 11,
|
|
'channel': inchans[i]},
|
|
{'msatoshi': 100000000,
|
|
'id': outnodes[i].info['id'],
|
|
'delay': 5,
|
|
'channel': outchans[i]}]
|
|
payment_hash = outnodes[i].rpc.invoice(100000000, "invoice2", "invoice2")['payment_hash']
|
|
to_pay.append(Payment(innodes[i], route, payment_hash))
|
|
|
|
# sendpay is async.
|
|
for p in to_pay:
|
|
p.innode.rpc.sendpay(p.route, p.payment_hash)
|
|
|
|
# Now restart l1 while traffic is flowing...
|
|
l1.restart()
|
|
|
|
# Wait for them to finish.
|
|
for n in innodes:
|
|
wait_for(lambda: 'pending' not in [p['status'] for p in n.rpc.listsendpays()['payments']])
|
|
|
|
|
|
@unittest.skipIf(not DEVELOPER, "need dev-disconnect")
|
|
def test_fail_unconfirmed(node_factory, bitcoind, executor):
|
|
"""Test that if we crash with an unconfirmed connection to a known
|
|
peer, we don't have a dangling peer in db"""
|
|
# = is a NOOP disconnect, but sets up file.
|
|
l1 = node_factory.get_node(disconnect=['=WIRE_OPEN_CHANNEL'])
|
|
l2 = node_factory.get_node()
|
|
|
|
# First one, we close by mutual agreement.
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fund_channel(l2, 200000, wait_for_active=True)
|
|
l1.rpc.close(l2.info['id'])
|
|
|
|
# Make sure it's closed
|
|
l1.wait_for_channel_onchain(l2.info['id'])
|
|
bitcoind.generate_block(1)
|
|
l1.daemon.wait_for_log('State changed from CLOSINGD_COMPLETE to FUNDING_SPEND_SEEN')
|
|
|
|
l1.stop()
|
|
# Mangle disconnect file so this time it blackholes....
|
|
with open(l1.daemon.disconnect_file, "w") as f:
|
|
f.write("0WIRE_OPEN_CHANNEL\n")
|
|
l1.start()
|
|
|
|
# Now we establish a new channel, which gets stuck.
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fundwallet(10**7)
|
|
executor.submit(l1.rpc.fundchannel, l2.info['id'], 100000)
|
|
|
|
l1.daemon.wait_for_log("dev_disconnect")
|
|
|
|
# Now complete old channel.
|
|
bitcoind.generate_block(100)
|
|
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
|
|
|
|
# And crash l1, which is stuck.
|
|
l1.daemon.kill()
|
|
|
|
# Now, restart and see if it can connect OK.
|
|
del l1.daemon.opts['dev-disconnect']
|
|
l1.start()
|
|
|
|
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
|
|
l1.fund_channel(l2, 200000, wait_for_active=True)
|
|
|
|
|
|
def test_change_chaining(node_factory, bitcoind):
|
|
"""Test change chaining of unconfirmed fundings
|
|
|
|
Change chaining is the case where one transaction is broadcast but not
|
|
confirmed yet and we already build a followup on top of the change. If the
|
|
first transaction doesn't confirm we may end up creating a series of
|
|
unconfirmable transactions. This is why we generally disallow chaining.
|
|
|
|
"""
|
|
l1, l2, l3 = node_factory.get_nodes(3)
|
|
l1.fundwallet(10**8) # This will create an output with 1 confirmation
|
|
|
|
# Now fund a channel from l1 to l2, that should succeed, with minconf=1 but not before
|
|
l1.connect(l2)
|
|
with pytest.raises(RpcError):
|
|
l1.rpc.fundchannel(l2.info['id'], 10**7, minconf=2)
|
|
l1.rpc.fundchannel(l2.info['id'], 10**7) # Defaults to minconf=1
|
|
|
|
# We don't have confirmed outputs anymore, so this should fail without minconf=0
|
|
l1.connect(l3)
|
|
with pytest.raises(RpcError):
|
|
l1.rpc.fundchannel(l3.info['id'], 10**7) # Defaults to minconf=1
|
|
l1.rpc.fundchannel(l3.info['id'], 10**7, minconf=0)
|
|
|