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crypto: make LazyTransform compabile with Streams1

Makes LazyTransform writable by Streams1 by assigning .writable = true
before the actual classes are loaded.

Fixes: https://github.com/nodejs/node/issues/12269
PR-URL: https://github.com/nodejs/node/pull/12380
Reviewed-By: Colin Ihrig <cjihrig@gmail.com>
Reviewed-By: James M Snell <jasnell@gmail.com>
Reviewed-By: Anna Henningsen <anna@addaleax.net>
v6
Matteo Collina 8 years ago
parent
commit
1ae172b272
  1. 2
      lib/internal/streams/lazy_transform.js
  2. 34
      test/parallel/test-crypto-lazy-transform-writable.js

2
lib/internal/streams/lazy_transform.js

@ -11,6 +11,8 @@ module.exports = LazyTransform;
function LazyTransform(options) {
this._options = options;
this.writable = true;
this.readable = true;
}
util.inherits(LazyTransform, stream.Transform);

34
test/parallel/test-crypto-lazy-transform-writable.js

@ -0,0 +1,34 @@
'use strict';
const common = require('../common');
const assert = require('assert');
const crypto = require('crypto');
const Stream = require('stream');
const util = require('util');
const hasher1 = crypto.createHash('sha256');
const hasher2 = crypto.createHash('sha256');
// Calculate the expected result.
hasher1.write(Buffer.from('hello world'));
hasher1.end();
const expected = hasher1.read().toString('hex');
function OldStream() {
Stream.call(this);
this.readable = true;
}
util.inherits(OldStream, Stream);
const stream = new OldStream();
stream.pipe(hasher2).on('finish', common.mustCall(function() {
const hash = hasher2.read().toString('hex');
assert.strictEqual(expected, hash);
}));
stream.emit('data', Buffer.from('hello'));
stream.emit('data', Buffer.from(' world'));
stream.emit('end');
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