test: more robust check for location of `node.exe`

look for the actual produced `exe` not just the directory

PR-URL: https://github.com/nodejs/node/pull/12120
Reviewed-By: Ben Noordhuis <info@bnoordhuis.nl>
Reviewed-By: James M Snell <jasnell@gmail.com>
Reviewed-By: Gibson Fahnestock <gibfahn@gmail.com>
Reviewed-By: Nikolai Vavilov <vvnicholas@gmail.com>

tools/test.py

@@ -893,15 +893,13 @@ class Context(object):
     # http://code.google.com/p/gyp/issues/detail?id=40
     # It will put the builds into Release/node.exe or Debug/node.exe
     if utils.IsWindows():
-      out_dir = os.path.join(dirname(__file__), "..", "out")
+      if not exists(name + '.exe'):
-      if not exists(out_dir):
+        name = name.replace('out/', '')
-        if mode == 'debug':
-          name = os.path.abspath('Debug/node.exe')
-        else:
-          name = os.path.abspath('Release/node.exe')
-      else:
       name = os.path.abspath(name + '.exe')
 
+    if not exists(name):
+      raise ValueError('Could not find executable. Should be ' + name)
+
     return name
 
   def GetVmFlags(self, testcase, mode):